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Negative Resistance



Announcing the arrival of Valued Associate #679: Cesar Manara
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}







3












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$












  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    56 mins ago


















3












$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$












  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    56 mins ago














3












3








3





$begingroup$


I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.










share|improve this question











$endgroup$




I am a bit confused about the physical meaning of negative resistance.



Mathematically, a component which has negative resistance shows a decreasing voltage across its terminal when the current inside it grows, and vice versa. But how is this physically possible?



Somewhere I have read that an example of component with negative resistance is a voltage source. But I do not understand this statement, since a voltage source is a component which at most shows a (positive) internal resistance.







voltage current resistors resistance voltage-source






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 1 hour ago









Marcus Müller

35.5k363101




35.5k363101










asked 1 hour ago









Kinka-ByoKinka-Byo

762




762












  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    56 mins ago


















  • $begingroup$
    Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
    $endgroup$
    – Michel Keijzers
    1 hour ago






  • 1




    $begingroup$
    Minus R will provide power, not dissipate power.
    $endgroup$
    – analogsystemsrf
    56 mins ago
















$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
1 hour ago




$begingroup$
Maybe if you see a circuit with two resistors in series (voltage divider), having in the middle 2.5V, a component with negative resistance can be said to 'add voltage' instead of removing voltage... but I leave a real answer to the experts here ;-)
$endgroup$
– Michel Keijzers
1 hour ago




1




1




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
56 mins ago




$begingroup$
Minus R will provide power, not dissipate power.
$endgroup$
– analogsystemsrf
56 mins ago










7 Answers
7






active

oldest

votes


















4












$begingroup$

There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



enter image description here



A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.





If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





schematic





simulate this circuit – Schematic created using CircuitLab



The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    That is really a fine choice of an example device you picked.
    $endgroup$
    – The Photon
    1 hour ago










  • $begingroup$
    @ThePhoton LOL, great minds and all that.
    $endgroup$
    – Spehro Pefhany
    53 mins ago












  • $begingroup$
    Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
    $endgroup$
    – J...
    18 mins ago



















2












$begingroup$

Anything that drops in voltage with a rise in current has a negative resistance.



Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



https://en.wikipedia.org/wiki/Negative_resistance






share|improve this answer









$endgroup$





















    2












    $begingroup$

    In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



    Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



    Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






    share|improve this answer









    $endgroup$





















      1












      $begingroup$


      Somewhere I have read that an example of component with negative
      resistance is a voltage source. But I do not understand this
      statement, since a voltage source is a component which at most shows a
      (positive) internal resistance.




      Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



      For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





      schematic





      simulate this circuit – Schematic created using CircuitLab
      Using the built-in circuit simulator, $ R_{load} $ was swept from 5 ohms up to 15 ohms:




      • at 5 ohms, voltage drop across Rload is 4.322V


      • at 15 ohms, voltage drop across Rload is 3.993V



      The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






      share|improve this answer









      $endgroup$





















        0












        $begingroup$

        A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



        The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



        enter image description here






        share|improve this answer









        $endgroup$





















          0












          $begingroup$


          But how is this physically possible?




          Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



          enter image description here



          (image source)



          In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



          It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




          Somewhere I have read that an example of component with negative resistance is a voltage source.




          Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



          This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






          share|improve this answer









          $endgroup$





















            0












            $begingroup$

            In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



            Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



            Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





            schematic





            simulate this circuit – Schematic created using CircuitLab



            Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



            A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






            share|improve this answer











            $endgroup$














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              7 Answers
              7






              active

              oldest

              votes








              7 Answers
              7






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              4












              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.





              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$









              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                53 mins ago












              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                18 mins ago
















              4












              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.





              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$









              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                53 mins ago












              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                18 mins ago














              4












              4








              4





              $begingroup$

              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.





              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.






              share|improve this answer











              $endgroup$



              There are a number of mechanisms that result in a region where locally increasing voltage results in locally decreasing current. For example, an Esaki (tunnel) diode.



              enter image description here



              A common example would be a switching power supply with a steady load. Assuming the efficiency is more-or-less constant, increasing the input voltage results in less current being drawn. It is always consuming energy though.



              A stand-alone component that exhibits negative resistance (rather than negative differential resistance) is not possible without some kind of energy source within the component, otherwise it would violate conservation of energy ($P = E^2/R$) and negative P would indicate it is acting as a power source.





              If you want to play with a negative resistance effect, one way (assuming you don't mind one end being grounded) is to use a negative impedance converter:





              schematic





              simulate this circuit – Schematic created using CircuitLab



              The above circuit acts like a -10K resistor with one end grounded (within its linear range), and works down to about zero volts. Any power it produces comes from the op-amp supplies.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 48 mins ago

























              answered 1 hour ago









              Spehro PefhanySpehro Pefhany

              215k5164438




              215k5164438








              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                53 mins ago












              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                18 mins ago














              • 1




                $begingroup$
                That is really a fine choice of an example device you picked.
                $endgroup$
                – The Photon
                1 hour ago










              • $begingroup$
                @ThePhoton LOL, great minds and all that.
                $endgroup$
                – Spehro Pefhany
                53 mins ago












              • $begingroup$
                Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
                $endgroup$
                – J...
                18 mins ago








              1




              1




              $begingroup$
              That is really a fine choice of an example device you picked.
              $endgroup$
              – The Photon
              1 hour ago




              $begingroup$
              That is really a fine choice of an example device you picked.
              $endgroup$
              – The Photon
              1 hour ago












              $begingroup$
              @ThePhoton LOL, great minds and all that.
              $endgroup$
              – Spehro Pefhany
              53 mins ago






              $begingroup$
              @ThePhoton LOL, great minds and all that.
              $endgroup$
              – Spehro Pefhany
              53 mins ago














              $begingroup$
              Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
              $endgroup$
              – J...
              18 mins ago




              $begingroup$
              Your first example is really more about complex impedance and reactive effects. It doesn't really mean "negative resistance" in the sense of the real components of the circuit elements.
              $endgroup$
              – J...
              18 mins ago













              2












              $begingroup$

              Anything that drops in voltage with a rise in current has a negative resistance.



              Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



              https://en.wikipedia.org/wiki/Negative_resistance






              share|improve this answer









              $endgroup$


















                2












                $begingroup$

                Anything that drops in voltage with a rise in current has a negative resistance.



                Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                https://en.wikipedia.org/wiki/Negative_resistance






                share|improve this answer









                $endgroup$
















                  2












                  2








                  2





                  $begingroup$

                  Anything that drops in voltage with a rise in current has a negative resistance.



                  Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                  https://en.wikipedia.org/wiki/Negative_resistance






                  share|improve this answer









                  $endgroup$



                  Anything that drops in voltage with a rise in current has a negative resistance.



                  Power sources have this property. The passive components with incremental negative resistance include; any gas discharge bulb or arc, Avalanche effect diodes, Tunnel Diodes, SCR's during trigger phase.



                  https://en.wikipedia.org/wiki/Negative_resistance







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 1 hour ago









                  Sunnyskyguy EE75Sunnyskyguy EE75

                  72.2k227103




                  72.2k227103























                      2












                      $begingroup$

                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                      share|improve this answer









                      $endgroup$


















                        2












                        $begingroup$

                        In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                        Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                        Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                        share|improve this answer









                        $endgroup$
















                          2












                          2








                          2





                          $begingroup$

                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).






                          share|improve this answer









                          $endgroup$



                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 58 mins ago









                          LvWLvW

                          14.9k21330




                          14.9k21330























                              1












                              $begingroup$


                              Somewhere I have read that an example of component with negative
                              resistance is a voltage source. But I do not understand this
                              statement, since a voltage source is a component which at most shows a
                              (positive) internal resistance.




                              Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                              For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                              schematic





                              simulate this circuit – Schematic created using CircuitLab
                              Using the built-in circuit simulator, $ R_{load} $ was swept from 5 ohms up to 15 ohms:




                              • at 5 ohms, voltage drop across Rload is 4.322V


                              • at 15 ohms, voltage drop across Rload is 3.993V



                              The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                              share|improve this answer









                              $endgroup$


















                                1












                                $begingroup$


                                Somewhere I have read that an example of component with negative
                                resistance is a voltage source. But I do not understand this
                                statement, since a voltage source is a component which at most shows a
                                (positive) internal resistance.




                                Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                schematic





                                simulate this circuit – Schematic created using CircuitLab
                                Using the built-in circuit simulator, $ R_{load} $ was swept from 5 ohms up to 15 ohms:




                                • at 5 ohms, voltage drop across Rload is 4.322V


                                • at 15 ohms, voltage drop across Rload is 3.993V



                                The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                share|improve this answer









                                $endgroup$
















                                  1












                                  1








                                  1





                                  $begingroup$


                                  Somewhere I have read that an example of component with negative
                                  resistance is a voltage source. But I do not understand this
                                  statement, since a voltage source is a component which at most shows a
                                  (positive) internal resistance.




                                  Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                  For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                  schematic





                                  simulate this circuit – Schematic created using CircuitLab
                                  Using the built-in circuit simulator, $ R_{load} $ was swept from 5 ohms up to 15 ohms:




                                  • at 5 ohms, voltage drop across Rload is 4.322V


                                  • at 15 ohms, voltage drop across Rload is 3.993V



                                  The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.






                                  share|improve this answer









                                  $endgroup$




                                  Somewhere I have read that an example of component with negative
                                  resistance is a voltage source. But I do not understand this
                                  statement, since a voltage source is a component which at most shows a
                                  (positive) internal resistance.




                                  Perhaps a voltage source is mentioned, because we all know that an ideal voltage source should have zero internal resistance: a good one will have a small positive resistance, to which is added any wire resistance going to the load.



                                  For an electronically regulated supply, it is possible to force output resistance past zero into negative resistance region. This is done by routing some of the load current so that regulating voltage node is adjusted in such a direction that output voltage is forced up. An example of the common LM317 regulator having negative output resistance is shown below - beware, some loads produce wild results:





                                  schematic





                                  simulate this circuit – Schematic created using CircuitLab
                                  Using the built-in circuit simulator, $ R_{load} $ was swept from 5 ohms up to 15 ohms:




                                  • at 5 ohms, voltage drop across Rload is 4.322V


                                  • at 15 ohms, voltage drop across Rload is 3.993V



                                  The result of that 1-ohm resistor, (and the direction of Rload's current going through it) forces this voltage supply to have negative resistance: at heavier loads, voltage across the load resistor goes up.







                                  share|improve this answer












                                  share|improve this answer



                                  share|improve this answer










                                  answered 30 mins ago









                                  glen_geekglen_geek

                                  9,78611016




                                  9,78611016























                                      0












                                      $begingroup$

                                      A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                      The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                      enter image description here






                                      share|improve this answer









                                      $endgroup$


















                                        0












                                        $begingroup$

                                        A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                        The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                        enter image description here






                                        share|improve this answer









                                        $endgroup$
















                                          0












                                          0








                                          0





                                          $begingroup$

                                          A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                          The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                          enter image description here






                                          share|improve this answer









                                          $endgroup$



                                          A perfect negative resistor is impossible, but a device can have negative resistance characteristics over a limited range.



                                          The resistance of a non-linear device varies and at a given voltage the equivalent resistance is equal to the slope of the line. If the slope is negative in a range, that range has negative resistance.



                                          enter image description here







                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered 1 hour ago









                                          Mattman944Mattman944

                                          3015




                                          3015























                                              0












                                              $begingroup$


                                              But how is this physically possible?




                                              Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                              enter image description here



                                              (image source)



                                              In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                              It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                              Somewhere I have read that an example of component with negative resistance is a voltage source.




                                              Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                              This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                              share|improve this answer









                                              $endgroup$


















                                                0












                                                $begingroup$


                                                But how is this physically possible?




                                                Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                                enter image description here



                                                (image source)



                                                In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                                It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                                Somewhere I have read that an example of component with negative resistance is a voltage source.




                                                Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                                This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                                share|improve this answer









                                                $endgroup$
















                                                  0












                                                  0








                                                  0





                                                  $begingroup$


                                                  But how is this physically possible?




                                                  Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                                  enter image description here



                                                  (image source)



                                                  In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                                  It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                                  Somewhere I have read that an example of component with negative resistance is a voltage source.




                                                  Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                                  This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.






                                                  share|improve this answer









                                                  $endgroup$




                                                  But how is this physically possible?




                                                  Some components, like Esaki diodes and glow tubes, have an I-V curve that is entirely in the I and III quadrants, but has a negative slope region over a limited range. In this region, a small-signal model of the device will have negative resistance.



                                                  enter image description here



                                                  (image source)



                                                  In the Esaki diode, this behavior is caused by tunneling current that is possible at low bias but not at higher bias voltage.



                                                  It's also possible to make an op-amp circuit with negative input resistance over a limited range. There the I-V curve can even pass through the II and IV quadrants since power can be supplied from the op-amp's power terminals.




                                                  Somewhere I have read that an example of component with negative resistance is a voltage source.




                                                  Looking at the input side of a regulated switching supply with a fixed load, it will often appear as a negative resistance.



                                                  This is because it is a constant power load. If the input voltage drops, the regulator circuit will increase the current drawn in order to continue supplying the load with the desired output voltage.







                                                  share|improve this answer












                                                  share|improve this answer



                                                  share|improve this answer










                                                  answered 1 hour ago









                                                  The PhotonThe Photon

                                                  87.9k399205




                                                  87.9k399205























                                                      0












                                                      $begingroup$

                                                      In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                                      Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                                      Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                                      schematic





                                                      simulate this circuit – Schematic created using CircuitLab



                                                      Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                                      A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                                      share|improve this answer











                                                      $endgroup$


















                                                        0












                                                        $begingroup$

                                                        In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                                        Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                                        Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                                        schematic





                                                        simulate this circuit – Schematic created using CircuitLab



                                                        Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                                        A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                                        share|improve this answer











                                                        $endgroup$
















                                                          0












                                                          0








                                                          0





                                                          $begingroup$

                                                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                                          schematic





                                                          simulate this circuit – Schematic created using CircuitLab



                                                          Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                                          A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.






                                                          share|improve this answer











                                                          $endgroup$



                                                          In this context, we have to discriminate between (1) pure differential (dynamic) neg. resistances (as shown in the examples of the other answers) and (b) a static negative resistance. My following answer concerns only the static negative resistor:



                                                          Such an element does not "consume" a current - driven by a voltage source, but - the other way round - it drives a current (prop. to the voltage) in an opposite direction into the voltage source.



                                                          Hence. it is a voltage-controlled current source. For such circuits only active realisations are possible (using transistors or - in most cases - opamps). The most popular circuit is the NIC (Negative-Impedance Converter).





                                                          schematic





                                                          simulate this circuit – Schematic created using CircuitLab



                                                          Comments: The shown NIC is stable as long as the source resistance of the voltage source (not shown in the figure) is smaller than R1. These NIC blocks are use for undamping filters, oscillators and other systems with unwanted positive (parasitic) resistances. Mathematically, they can be treated as "normal" resistors in series and parallel combinations - however, with a negative sign, of course.



                                                          A very popular application is the "NIC integrator" (or "Deboo integrator"), where an NIC block is connected to the common node of a simple R-C lowpass. In this case, the NIC can compensate the pos. resistor R - thus resembling a current source which loads the intergating capacitor.







                                                          share|improve this answer














                                                          share|improve this answer



                                                          share|improve this answer








                                                          edited 35 mins ago

























                                                          answered 48 mins ago









                                                          LvWLvW

                                                          14.9k21330




                                                          14.9k21330






























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