QGIS: use geometry from different layer in symbology expressionCopying Symbology between layers with...

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QGIS: use geometry from different layer in symbology expression


Copying Symbology between layers with different numbers of featuresWhere are the Expression-based Labeling options in QGIS?How to Display Overlapping Lines?QGIS expression: select from <layer> possible?Applying symbology to a layer with python, How to only have symbology in TOC that the sub layer hasCreating symbology for polygon layer which has opaque outlines but transparent colored fills using ArcGIS for Desktop?Arcpy ApplySymbologyFromLayer color problems with extentIs there a way to assign a feature from the majority of points to a polygon with *join attribute by location* QGIS 2.18Polygon layer symbology not displaying correctly in QGIS 3Create multipoint layer from array by expression













2















I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).



I have a second layer with polygons, visible as the partly-transparent arc-area in red.



The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer



What step do i have to take to get this done.



example without last step










share|improve this question





























    2















    I have a project with multiple layers.
    The purple dots are from a pointfile with the symbology-expression:
    z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).



    I have a second layer with polygons, visible as the partly-transparent arc-area in red.



    The next step i want to make in my project is to:
    have the purple dots appear only if:
    z($geometry)>'14.5' AND
    the x-y of that spot is within the geographical extent of the polygon from the second layer



    What step do i have to take to get this done.



    example without last step










    share|improve this question



























      2












      2








      2








      I have a project with multiple layers.
      The purple dots are from a pointfile with the symbology-expression:
      z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).



      I have a second layer with polygons, visible as the partly-transparent arc-area in red.



      The next step i want to make in my project is to:
      have the purple dots appear only if:
      z($geometry)>'14.5' AND
      the x-y of that spot is within the geographical extent of the polygon from the second layer



      What step do i have to take to get this done.



      example without last step










      share|improve this question
















      I have a project with multiple layers.
      The purple dots are from a pointfile with the symbology-expression:
      z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).



      I have a second layer with polygons, visible as the partly-transparent arc-area in red.



      The next step i want to make in my project is to:
      have the purple dots appear only if:
      z($geometry)>'14.5' AND
      the x-y of that spot is within the geographical extent of the polygon from the second layer



      What step do i have to take to get this done.



      example without last step







      qgis symbology z-value






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago









      Matthias Kuhn

      18.9k14890




      18.9k14890










      asked 2 hours ago









      CaptainAhabCaptainAhab

      656




      656






















          1 Answer
          1






          active

          oldest

          votes


















          2














          Your question is very similar to what I've done here recently.



          I used expression:



          if(
          within($geometry,geometry(get_feature(layer,attribute,value))),
          result_when_true,
          result_when_false
          )


          In your case step 1: filter data table by



          z($geometry)> '14.5'


          step 2: paste expression in point symbology layer (see gif to find where)



          if(
          within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
          1,
          0
          )


          You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.



          That's it.



          enter image description here






          share|improve this answer


























          • Good answer! Would it work to drop the if-part completely and just use within(...)?

            – Matthias Kuhn
            14 mins ago











          Your Answer








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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          Your question is very similar to what I've done here recently.



          I used expression:



          if(
          within($geometry,geometry(get_feature(layer,attribute,value))),
          result_when_true,
          result_when_false
          )


          In your case step 1: filter data table by



          z($geometry)> '14.5'


          step 2: paste expression in point symbology layer (see gif to find where)



          if(
          within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
          1,
          0
          )


          You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.



          That's it.



          enter image description here






          share|improve this answer


























          • Good answer! Would it work to drop the if-part completely and just use within(...)?

            – Matthias Kuhn
            14 mins ago
















          2














          Your question is very similar to what I've done here recently.



          I used expression:



          if(
          within($geometry,geometry(get_feature(layer,attribute,value))),
          result_when_true,
          result_when_false
          )


          In your case step 1: filter data table by



          z($geometry)> '14.5'


          step 2: paste expression in point symbology layer (see gif to find where)



          if(
          within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
          1,
          0
          )


          You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.



          That's it.



          enter image description here






          share|improve this answer


























          • Good answer! Would it work to drop the if-part completely and just use within(...)?

            – Matthias Kuhn
            14 mins ago














          2












          2








          2







          Your question is very similar to what I've done here recently.



          I used expression:



          if(
          within($geometry,geometry(get_feature(layer,attribute,value))),
          result_when_true,
          result_when_false
          )


          In your case step 1: filter data table by



          z($geometry)> '14.5'


          step 2: paste expression in point symbology layer (see gif to find where)



          if(
          within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
          1,
          0
          )


          You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.



          That's it.



          enter image description here






          share|improve this answer















          Your question is very similar to what I've done here recently.



          I used expression:



          if(
          within($geometry,geometry(get_feature(layer,attribute,value))),
          result_when_true,
          result_when_false
          )


          In your case step 1: filter data table by



          z($geometry)> '14.5'


          step 2: paste expression in point symbology layer (see gif to find where)



          if(
          within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
          1,
          0
          )


          You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.



          That's it.



          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 36 mins ago

























          answered 1 hour ago









          VitruviusVitruvius

          429210




          429210













          • Good answer! Would it work to drop the if-part completely and just use within(...)?

            – Matthias Kuhn
            14 mins ago



















          • Good answer! Would it work to drop the if-part completely and just use within(...)?

            – Matthias Kuhn
            14 mins ago

















          Good answer! Would it work to drop the if-part completely and just use within(...)?

          – Matthias Kuhn
          14 mins ago





          Good answer! Would it work to drop the if-part completely and just use within(...)?

          – Matthias Kuhn
          14 mins ago


















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