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How to invert Logic Gate input in Circuitikz

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I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)

documentclass[a4paper,12pt]{article}



usepackage{tikz} %vectorgraphics

usetikzlibrary{shapes,arrows,shadows,

decorations.pathreplacing,backgrounds,calc} 

%graph/flowchart

usepackage[siunitx]{circuitikz}



begin{document}

begin{circuitikz} draw



(0,0) node[nand port] (nand1) {}

(3,0) node[nand port] (nand2) {}

(5,0) node[nand port] (nand3) {}



(3,2) node[nand port] (nand4) {}

(5,2) node[nand port] (nand5) {}



(3,4) node[nand port] (nand6) {}

(5,4) node[nand port] (nand7) {}



(0,4) node[nand port] (nand8) {}



(nand1.out) |- (nand2.in 2)

(nand2.out) -| node[circ,midway]{} (nand3.in 1)

(nand2.out) -| (nand3.in 2)



(nand8.out) |- (nand6.in 1)

(nand6.out) -| node[circ,midway]{} (nand7.in 2)

(nand6.out) -| (nand7.in 1)



(nand4.out) -| node[circ,midway]{} (nand5.in 2)

(nand4.out) -| (nand5.in 1)



(-2,1) node(B1)[anchor=east] {B}

(-2,1) -| node[circ,midway]{} (nand1.in 1) 

to[short,*-] (nand1.in 2)

(-2,1) -| (nand4.in 2)

(1,1) node[circ]{} |- (nand6.in 2)





(-2,3) node[anchor=east] {A}

(-2,3) -| node[circ,midway]{} (nand8.in 2) 

to[short,*-] (nand8.in 1)

(-2,3) -| (nand4.in 1)

(0.5,3) node[circ]{} |- (nand2.in 1)



(6,1.97) node[anchor=east] {O2}

(6,0.0) node[anchor=east] {O3}

(6,4) node[anchor=east] {O1}



;end{circuitikz}



end{document}

circuitikz logic

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asked 7 mins ago

Roman StadlerRoman Stadler

133

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Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment | 

0

I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)

documentclass[a4paper,12pt]{article}



usepackage{tikz} %vectorgraphics

usetikzlibrary{shapes,arrows,shadows,

decorations.pathreplacing,backgrounds,calc} 

%graph/flowchart

usepackage[siunitx]{circuitikz}



begin{document}

begin{circuitikz} draw



(0,0) node[nand port] (nand1) {}

(3,0) node[nand port] (nand2) {}

(5,0) node[nand port] (nand3) {}



(3,2) node[nand port] (nand4) {}

(5,2) node[nand port] (nand5) {}



(3,4) node[nand port] (nand6) {}

(5,4) node[nand port] (nand7) {}



(0,4) node[nand port] (nand8) {}



(nand1.out) |- (nand2.in 2)

(nand2.out) -| node[circ,midway]{} (nand3.in 1)

(nand2.out) -| (nand3.in 2)



(nand8.out) |- (nand6.in 1)

(nand6.out) -| node[circ,midway]{} (nand7.in 2)

(nand6.out) -| (nand7.in 1)



(nand4.out) -| node[circ,midway]{} (nand5.in 2)

(nand4.out) -| (nand5.in 1)



(-2,1) node(B1)[anchor=east] {B}

(-2,1) -| node[circ,midway]{} (nand1.in 1) 

to[short,*-] (nand1.in 2)

(-2,1) -| (nand4.in 2)

(1,1) node[circ]{} |- (nand6.in 2)





(-2,3) node[anchor=east] {A}

(-2,3) -| node[circ,midway]{} (nand8.in 2) 

to[short,*-] (nand8.in 1)

(-2,3) -| (nand4.in 1)

(0.5,3) node[circ]{} |- (nand2.in 1)



(6,1.97) node[anchor=east] {O2}

(6,0.0) node[anchor=east] {O3}

(6,4) node[anchor=east] {O1}



;end{circuitikz}



end{document}

circuitikz logic

share

asked 7 mins ago

Roman StadlerRoman Stadler

133

New contributor

Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I have drawn the following circuit, but how could the inputs of a Logic Gate be inverted? (As in the scanned picture, but it does not matter which gate exactly, just generally)

documentclass[a4paper,12pt]{article}



usepackage{tikz} %vectorgraphics

usetikzlibrary{shapes,arrows,shadows,

decorations.pathreplacing,backgrounds,calc} 

%graph/flowchart

usepackage[siunitx]{circuitikz}



begin{document}

begin{circuitikz} draw



(0,0) node[nand port] (nand1) {}

(3,0) node[nand port] (nand2) {}

(5,0) node[nand port] (nand3) {}



(3,2) node[nand port] (nand4) {}

(5,2) node[nand port] (nand5) {}



(3,4) node[nand port] (nand6) {}

(5,4) node[nand port] (nand7) {}



(0,4) node[nand port] (nand8) {}



(nand1.out) |- (nand2.in 2)

(nand2.out) -| node[circ,midway]{} (nand3.in 1)

(nand2.out) -| (nand3.in 2)



(nand8.out) |- (nand6.in 1)

(nand6.out) -| node[circ,midway]{} (nand7.in 2)

(nand6.out) -| (nand7.in 1)



(nand4.out) -| node[circ,midway]{} (nand5.in 2)

(nand4.out) -| (nand5.in 1)



(-2,1) node(B1)[anchor=east] {B}

(-2,1) -| node[circ,midway]{} (nand1.in 1) 

to[short,*-] (nand1.in 2)

(-2,1) -| (nand4.in 2)

(1,1) node[circ]{} |- (nand6.in 2)





(-2,3) node[anchor=east] {A}

(-2,3) -| node[circ,midway]{} (nand8.in 2) 

to[short,*-] (nand8.in 1)

(-2,3) -| (nand4.in 1)

(0.5,3) node[circ]{} |- (nand2.in 1)



(6,1.97) node[anchor=east] {O2}

(6,0.0) node[anchor=east] {O3}

(6,4) node[anchor=east] {O1}



;end{circuitikz}



end{document}

circuitikz logic

share

asked 7 mins ago

Roman StadlerRoman Stadler

133

New contributor

Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

documentclass[a4paper,12pt]{article}



usepackage{tikz} %vectorgraphics

usetikzlibrary{shapes,arrows,shadows,

decorations.pathreplacing,backgrounds,calc} 

%graph/flowchart

usepackage[siunitx]{circuitikz}



begin{document}

begin{circuitikz} draw



(0,0) node[nand port] (nand1) {}

(3,0) node[nand port] (nand2) {}

(5,0) node[nand port] (nand3) {}



(3,2) node[nand port] (nand4) {}

(5,2) node[nand port] (nand5) {}



(3,4) node[nand port] (nand6) {}

(5,4) node[nand port] (nand7) {}



(0,4) node[nand port] (nand8) {}



(nand1.out) |- (nand2.in 2)

(nand2.out) -| node[circ,midway]{} (nand3.in 1)

(nand2.out) -| (nand3.in 2)



(nand8.out) |- (nand6.in 1)

(nand6.out) -| node[circ,midway]{} (nand7.in 2)

(nand6.out) -| (nand7.in 1)



(nand4.out) -| node[circ,midway]{} (nand5.in 2)

(nand4.out) -| (nand5.in 1)



(-2,1) node(B1)[anchor=east] {B}

(-2,1) -| node[circ,midway]{} (nand1.in 1) 

to[short,*-] (nand1.in 2)

(-2,1) -| (nand4.in 2)

(1,1) node[circ]{} |- (nand6.in 2)





(-2,3) node[anchor=east] {A}

(-2,3) -| node[circ,midway]{} (nand8.in 2) 

to[short,*-] (nand8.in 1)

(-2,3) -| (nand4.in 1)

(0.5,3) node[circ]{} |- (nand2.in 1)



(6,1.97) node[anchor=east] {O2}

(6,0.0) node[anchor=east] {O3}

(6,4) node[anchor=east] {O1}



;end{circuitikz}



end{document}

share

asked 7 mins ago

Roman StadlerRoman Stadler

133

New contributor

Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 7 mins ago

Roman StadlerRoman Stadler

133

New contributor

Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 7 mins ago

Roman StadlerRoman Stadler

133

New contributor

Roman Stadler is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 7 mins ago

Roman StadlerRoman Stadler

133