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Calculate of total length of edges in Voronoi diagram


Finding the perimeter, area and number of sides of a Voronoi cellVoronoi diagrams for generators other than pointsUsing TetGen in Mathematica to get 3D Voronoi diagramBounded Voronoi DiagramSite - Cell Correspondence in Voronoi Diagram obtained via VoronoiMeshTriangulated Mesh from Voronoi DiagramAreas of Voronoi cells from an image fileHow to draw this 3D Voronoi Diagram?Approximating Voronoi diagram without any distance checksHow can I get the vertices of each polygon of a Voronoi diagram?













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Does anyone have any suggestions how to determine the total sum of edges length in a Voronoi diagram?










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    1 hour ago
















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Does anyone have any suggestions how to determine the total sum of edges length in a Voronoi diagram?










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Mati Ger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    Welcome to Mathematica.SE. Are you sure you are posting on the right site? There is nothing in your question making it clear that it is concerned with Mathematica software.
    $endgroup$
    – m_goldberg
    1 hour ago














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4








4





$begingroup$


Does anyone have any suggestions how to determine the total sum of edges length in a Voronoi diagram?










share|improve this question







New contributor




Mati Ger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Does anyone have any suggestions how to determine the total sum of edges length in a Voronoi diagram?







computational-geometry






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Mati Ger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question







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asked 1 hour ago









Mati GerMati Ger

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New contributor





Mati Ger is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Welcome to Mathematica.SE. Are you sure you are posting on the right site? There is nothing in your question making it clear that it is concerned with Mathematica software.
    $endgroup$
    – m_goldberg
    1 hour ago


















  • $begingroup$
    Welcome to Mathematica.SE. Are you sure you are posting on the right site? There is nothing in your question making it clear that it is concerned with Mathematica software.
    $endgroup$
    – m_goldberg
    1 hour ago
















$begingroup$
Welcome to Mathematica.SE. Are you sure you are posting on the right site? There is nothing in your question making it clear that it is concerned with Mathematica software.
$endgroup$
– m_goldberg
1 hour ago




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– m_goldberg
1 hour ago










2 Answers
2






active

oldest

votes


















3












$begingroup$

SeedRandom[1]
pts = RandomReal[{-1, 1}, {5, 2}];
vm = VoronoiMesh[pts]
MeshCellCount[vm, 1]



16




lengths = RegionMeasure /@ MeshPrimitives[vm, 1]



{0.60034, 0.672996, 0.403197, 0.793131, 0.596543, 0.920977, 1.03974, 1.12238, 0.322772, 1.05995, 0.854316, 0.985915, 0.0806386, 0.844254, 0.264125, 1.72809}




Total[lengths]



12.2894




Alternatively, you can use ArcLength in place of RegionMeasure:



lengths == ArcLength /@ MeshPrimitives[vm, 1]
True





share|improve this answer









$endgroup$





















    3












    $begingroup$

    SeedRandom[1234];
    R = VoronoiMesh[RandomReal[{-1, 1}, {20, 2}]];
    Total[PropertyValue[{R, 1}, MeshCellMeasure]]



    31.1601







    share|improve this answer









    $endgroup$













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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3












      $begingroup$

      SeedRandom[1]
      pts = RandomReal[{-1, 1}, {5, 2}];
      vm = VoronoiMesh[pts]
      MeshCellCount[vm, 1]



      16




      lengths = RegionMeasure /@ MeshPrimitives[vm, 1]



      {0.60034, 0.672996, 0.403197, 0.793131, 0.596543, 0.920977, 1.03974, 1.12238, 0.322772, 1.05995, 0.854316, 0.985915, 0.0806386, 0.844254, 0.264125, 1.72809}




      Total[lengths]



      12.2894




      Alternatively, you can use ArcLength in place of RegionMeasure:



      lengths == ArcLength /@ MeshPrimitives[vm, 1]
      True





      share|improve this answer









      $endgroup$


















        3












        $begingroup$

        SeedRandom[1]
        pts = RandomReal[{-1, 1}, {5, 2}];
        vm = VoronoiMesh[pts]
        MeshCellCount[vm, 1]



        16




        lengths = RegionMeasure /@ MeshPrimitives[vm, 1]



        {0.60034, 0.672996, 0.403197, 0.793131, 0.596543, 0.920977, 1.03974, 1.12238, 0.322772, 1.05995, 0.854316, 0.985915, 0.0806386, 0.844254, 0.264125, 1.72809}




        Total[lengths]



        12.2894




        Alternatively, you can use ArcLength in place of RegionMeasure:



        lengths == ArcLength /@ MeshPrimitives[vm, 1]
        True





        share|improve this answer









        $endgroup$
















          3












          3








          3





          $begingroup$

          SeedRandom[1]
          pts = RandomReal[{-1, 1}, {5, 2}];
          vm = VoronoiMesh[pts]
          MeshCellCount[vm, 1]



          16




          lengths = RegionMeasure /@ MeshPrimitives[vm, 1]



          {0.60034, 0.672996, 0.403197, 0.793131, 0.596543, 0.920977, 1.03974, 1.12238, 0.322772, 1.05995, 0.854316, 0.985915, 0.0806386, 0.844254, 0.264125, 1.72809}




          Total[lengths]



          12.2894




          Alternatively, you can use ArcLength in place of RegionMeasure:



          lengths == ArcLength /@ MeshPrimitives[vm, 1]
          True





          share|improve this answer









          $endgroup$



          SeedRandom[1]
          pts = RandomReal[{-1, 1}, {5, 2}];
          vm = VoronoiMesh[pts]
          MeshCellCount[vm, 1]



          16




          lengths = RegionMeasure /@ MeshPrimitives[vm, 1]



          {0.60034, 0.672996, 0.403197, 0.793131, 0.596543, 0.920977, 1.03974, 1.12238, 0.322772, 1.05995, 0.854316, 0.985915, 0.0806386, 0.844254, 0.264125, 1.72809}




          Total[lengths]



          12.2894




          Alternatively, you can use ArcLength in place of RegionMeasure:



          lengths == ArcLength /@ MeshPrimitives[vm, 1]
          True






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 57 mins ago









          kglrkglr

          186k10202421




          186k10202421























              3












              $begingroup$

              SeedRandom[1234];
              R = VoronoiMesh[RandomReal[{-1, 1}, {20, 2}]];
              Total[PropertyValue[{R, 1}, MeshCellMeasure]]



              31.1601







              share|improve this answer









              $endgroup$


















                3












                $begingroup$

                SeedRandom[1234];
                R = VoronoiMesh[RandomReal[{-1, 1}, {20, 2}]];
                Total[PropertyValue[{R, 1}, MeshCellMeasure]]



                31.1601







                share|improve this answer









                $endgroup$
















                  3












                  3








                  3





                  $begingroup$

                  SeedRandom[1234];
                  R = VoronoiMesh[RandomReal[{-1, 1}, {20, 2}]];
                  Total[PropertyValue[{R, 1}, MeshCellMeasure]]



                  31.1601







                  share|improve this answer









                  $endgroup$



                  SeedRandom[1234];
                  R = VoronoiMesh[RandomReal[{-1, 1}, {20, 2}]];
                  Total[PropertyValue[{R, 1}, MeshCellMeasure]]



                  31.1601








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 56 mins ago









                  Henrik SchumacherHenrik Schumacher

                  54.9k474153




                  54.9k474153






















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