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How to draw the image full of arrays
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I don't know how to make the image given below.
see my code
documentclass{article}
usepackage{tikz}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (s) at (0,0);
foreach num in {5,2,7,-5,16,12}{
node[minimum size=6mm, draw, rectangle] at (s) {num};
coordinate (s) at ($(s) + (1,0)$);
}
end{tikzpicture}
end{document}
Question : How to draw the image given in the diagram?
data-structures
edited Feb 24 at 16:56
leandriis
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
add a comment |
I don't know how to make the image given below.
see my code
documentclass{article}
usepackage{tikz}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (s) at (0,0);
foreach num in {5,2,7,-5,16,12}{
node[minimum size=6mm, draw, rectangle] at (s) {num};
coordinate (s) at ($(s) + (1,0)$);
}
end{tikzpicture}
end{document}
Question : How to draw the image given in the diagram?
data-structures
edited Feb 24 at 16:56
leandriis
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
add a comment |
I don't know how to make the image given below.
see my code
documentclass{article}
usepackage{tikz}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (s) at (0,0);
foreach num in {5,2,7,-5,16,12}{
node[minimum size=6mm, draw, rectangle] at (s) {num};
coordinate (s) at ($(s) + (1,0)$);
}
end{tikzpicture}
end{document}
Question : How to draw the image given in the diagram?
data-structures
edited Feb 24 at 16:56
leandriis
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
I don't know how to make the image given below.
see my code
documentclass{article}
usepackage{tikz}
usetikzlibrary{calc}
begin{document}
begin{tikzpicture}
coordinate (s) at (0,0);
foreach num in {5,2,7,-5,16,12}{
node[minimum size=6mm, draw, rectangle] at (s) {num};
coordinate (s) at ($(s) + (1,0)$);
}
end{tikzpicture}
end{document}
Question : How to draw the image given in the diagram?
data-structures
data-structures
edited Feb 24 at 16:56
leandriis
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
edited Feb 24 at 16:56
leandriis
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
edited Feb 24 at 16:56
leandriis
9,1771530
edited Feb 24 at 16:56
leandriis
9,1771530
edited Feb 24 at 16:56
leandriis
9,1771530
9,1771530
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
asked Feb 24 at 16:47
I_wil_break_wallI_wil_break_wall
1096
1096
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The following code (that is heavily inspired by Gonzalo Medina's answer) might serve as a starting point:
documentclass[border=2pt]{standalone}
usepackage{tikz}
usetikzlibrary{matrix,positioning,arrows.meta,arrows}
tikzset{
mymat/.style={
matrix of math nodes,
text height=2.5ex,
text depth=0.75ex,
text width=3.25ex,
align=center,
row sep=-pgflinewidth
},
}
begin{document}
begin{tikzpicture}[>=latex]
matrix[mymat,anchor=west,style={nodes=draw}]
at (0,0)
(mat1)
{
1\
2\
3\
4\
5\
6\
7\
};
matrix[mymat,right=of mat1,anchor=south,style={nodes={draw}},yshift=1.5cm]
(mat2)
{
1\
2\
};
matrix[mymat,right=of mat2,anchor=center,style={nodes={draw}}]
(mat3)
{
1\
2\
};
matrix[mymat,right=of mat3,anchor=center,style={nodes={draw}}]
(mat4)
{
1\
2\
};
matrix[mymat,right=of mat1,anchor=north,style={nodes={draw}},yshift=-1.5cm]
(mat5)
{
1\
2\
};
matrix[mymat,right=of mat5,anchor=center,style={nodes={draw}}]
(mat6)
{
1\
2\
};
matrix[mymat,right=of mat6,anchor=center,style={nodes={draw}}]
(mat7)
{
1\
2\
};
path[->]
(mat1-1-1.center) edge[bend left=50] node [left] {} (mat2-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=60] node [left] {} (mat3-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=70] node [left] {} (mat4-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=50] node [left] {} (mat5-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=60] node [left] {} (mat6-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=70] node [left] {} (mat7-1-1.north west);
end{tikzpicture}
end{document}
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
Instead ofcolumn sep=-pgflinewidthI would userow sep=-pgflinewidth.
– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
add a comment |
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1 Answer
1
active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The following code (that is heavily inspired by Gonzalo Medina's answer) might serve as a starting point:
documentclass[border=2pt]{standalone}
usepackage{tikz}
usetikzlibrary{matrix,positioning,arrows.meta,arrows}
tikzset{
mymat/.style={
matrix of math nodes,
text height=2.5ex,
text depth=0.75ex,
text width=3.25ex,
align=center,
row sep=-pgflinewidth
},
}
begin{document}
begin{tikzpicture}[>=latex]
matrix[mymat,anchor=west,style={nodes=draw}]
at (0,0)
(mat1)
{
1\
2\
3\
4\
5\
6\
7\
};
matrix[mymat,right=of mat1,anchor=south,style={nodes={draw}},yshift=1.5cm]
(mat2)
{
1\
2\
};
matrix[mymat,right=of mat2,anchor=center,style={nodes={draw}}]
(mat3)
{
1\
2\
};
matrix[mymat,right=of mat3,anchor=center,style={nodes={draw}}]
(mat4)
{
1\
2\
};
matrix[mymat,right=of mat1,anchor=north,style={nodes={draw}},yshift=-1.5cm]
(mat5)
{
1\
2\
};
matrix[mymat,right=of mat5,anchor=center,style={nodes={draw}}]
(mat6)
{
1\
2\
};
matrix[mymat,right=of mat6,anchor=center,style={nodes={draw}}]
(mat7)
{
1\
2\
};
path[->]
(mat1-1-1.center) edge[bend left=50] node [left] {} (mat2-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=60] node [left] {} (mat3-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=70] node [left] {} (mat4-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=50] node [left] {} (mat5-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=60] node [left] {} (mat6-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=70] node [left] {} (mat7-1-1.north west);
end{tikzpicture}
end{document}
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
Instead ofcolumn sep=-pgflinewidthI would userow sep=-pgflinewidth.
– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
add a comment |
The following code (that is heavily inspired by Gonzalo Medina's answer) might serve as a starting point:
documentclass[border=2pt]{standalone}
usepackage{tikz}
usetikzlibrary{matrix,positioning,arrows.meta,arrows}
tikzset{
mymat/.style={
matrix of math nodes,
text height=2.5ex,
text depth=0.75ex,
text width=3.25ex,
align=center,
row sep=-pgflinewidth
},
}
begin{document}
begin{tikzpicture}[>=latex]
matrix[mymat,anchor=west,style={nodes=draw}]
at (0,0)
(mat1)
{
1\
2\
3\
4\
5\
6\
7\
};
matrix[mymat,right=of mat1,anchor=south,style={nodes={draw}},yshift=1.5cm]
(mat2)
{
1\
2\
};
matrix[mymat,right=of mat2,anchor=center,style={nodes={draw}}]
(mat3)
{
1\
2\
};
matrix[mymat,right=of mat3,anchor=center,style={nodes={draw}}]
(mat4)
{
1\
2\
};
matrix[mymat,right=of mat1,anchor=north,style={nodes={draw}},yshift=-1.5cm]
(mat5)
{
1\
2\
};
matrix[mymat,right=of mat5,anchor=center,style={nodes={draw}}]
(mat6)
{
1\
2\
};
matrix[mymat,right=of mat6,anchor=center,style={nodes={draw}}]
(mat7)
{
1\
2\
};
path[->]
(mat1-1-1.center) edge[bend left=50] node [left] {} (mat2-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=60] node [left] {} (mat3-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=70] node [left] {} (mat4-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=50] node [left] {} (mat5-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=60] node [left] {} (mat6-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=70] node [left] {} (mat7-1-1.north west);
end{tikzpicture}
end{document}
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
Instead ofcolumn sep=-pgflinewidthI would userow sep=-pgflinewidth.
– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
add a comment |
The following code (that is heavily inspired by Gonzalo Medina's answer) might serve as a starting point:
documentclass[border=2pt]{standalone}
usepackage{tikz}
usetikzlibrary{matrix,positioning,arrows.meta,arrows}
tikzset{
mymat/.style={
matrix of math nodes,
text height=2.5ex,
text depth=0.75ex,
text width=3.25ex,
align=center,
row sep=-pgflinewidth
},
}
begin{document}
begin{tikzpicture}[>=latex]
matrix[mymat,anchor=west,style={nodes=draw}]
at (0,0)
(mat1)
{
1\
2\
3\
4\
5\
6\
7\
};
matrix[mymat,right=of mat1,anchor=south,style={nodes={draw}},yshift=1.5cm]
(mat2)
{
1\
2\
};
matrix[mymat,right=of mat2,anchor=center,style={nodes={draw}}]
(mat3)
{
1\
2\
};
matrix[mymat,right=of mat3,anchor=center,style={nodes={draw}}]
(mat4)
{
1\
2\
};
matrix[mymat,right=of mat1,anchor=north,style={nodes={draw}},yshift=-1.5cm]
(mat5)
{
1\
2\
};
matrix[mymat,right=of mat5,anchor=center,style={nodes={draw}}]
(mat6)
{
1\
2\
};
matrix[mymat,right=of mat6,anchor=center,style={nodes={draw}}]
(mat7)
{
1\
2\
};
path[->]
(mat1-1-1.center) edge[bend left=50] node [left] {} (mat2-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=60] node [left] {} (mat3-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=70] node [left] {} (mat4-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=50] node [left] {} (mat5-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=60] node [left] {} (mat6-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=70] node [left] {} (mat7-1-1.north west);
end{tikzpicture}
end{document}
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
The following code (that is heavily inspired by Gonzalo Medina's answer) might serve as a starting point:
documentclass[border=2pt]{standalone}
usepackage{tikz}
usetikzlibrary{matrix,positioning,arrows.meta,arrows}
tikzset{
mymat/.style={
matrix of math nodes,
text height=2.5ex,
text depth=0.75ex,
text width=3.25ex,
align=center,
row sep=-pgflinewidth
},
}
begin{document}
begin{tikzpicture}[>=latex]
matrix[mymat,anchor=west,style={nodes=draw}]
at (0,0)
(mat1)
{
1\
2\
3\
4\
5\
6\
7\
};
matrix[mymat,right=of mat1,anchor=south,style={nodes={draw}},yshift=1.5cm]
(mat2)
{
1\
2\
};
matrix[mymat,right=of mat2,anchor=center,style={nodes={draw}}]
(mat3)
{
1\
2\
};
matrix[mymat,right=of mat3,anchor=center,style={nodes={draw}}]
(mat4)
{
1\
2\
};
matrix[mymat,right=of mat1,anchor=north,style={nodes={draw}},yshift=-1.5cm]
(mat5)
{
1\
2\
};
matrix[mymat,right=of mat5,anchor=center,style={nodes={draw}}]
(mat6)
{
1\
2\
};
matrix[mymat,right=of mat6,anchor=center,style={nodes={draw}}]
(mat7)
{
1\
2\
};
path[->]
(mat1-1-1.center) edge[bend left=50] node [left] {} (mat2-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=60] node [left] {} (mat3-1-1.north west);
path[->]
(mat1-1-1.center) edge[bend left=70] node [left] {} (mat4-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=50] node [left] {} (mat5-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=60] node [left] {} (mat6-1-1.north west);
path[->]
(mat1-7-1.center) edge[bend left=70] node [left] {} (mat7-1-1.north west);
end{tikzpicture}
end{document}
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
edited 2 mins ago
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
answered Feb 24 at 19:34
leandriisleandriis
9,1771530
9,1771530
Instead ofcolumn sep=-pgflinewidthI would userow sep=-pgflinewidth.
– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
add a comment |
Instead ofcolumn sep=-pgflinewidthI would userow sep=-pgflinewidth.
– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
Instead of
column sep=-pgflinewidth I would use row sep=-pgflinewidth.– CarLaTeX
15 hours ago
Instead of
column sep=-pgflinewidth I would use row sep=-pgflinewidth.– CarLaTeX
15 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
Thanks for the answer but there are few problems with the answer. 1) pointing arrays are small 2) big arrays are is not numbered as required.
– I_wil_break_wall
12 hours ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
@CarLaTeX: Thank you for your commen. Indeed using row sep for a vertical array makes much more sense than using column sep.
– leandriis
2 mins ago
add a comment |
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