How to draw a tangent line to the following curve?How to draw tangent line of an arbitrary point on a path in...

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How to draw a tangent line to the following curve?


How to draw tangent line of an arbitrary point on a path in TikZHow to draw general functions and tangent linesHow to plot a function and its derivativeHow to recreate the following diagram?Tikz: unit tangent vectors to a curveTikZ scaling graphic and adjust node position and keep font sizeTikZ: non-linear tangent curveNormalized tangent vectors along a curveHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?How to draw the following diagram with tikz?How to draw the tangent vector at one endpoint of a curveTangent Lines Diagram Along Smooth CurveDrawing a curve tangent to a lineDraw tangent of an arbitrary curve at intersections













0















I want to draw the following diagram
enter image description here



Here is my MWE:



documentclass[border=3mm]{standalone}
usepackage{pgfplots}
pgfplotsset{width=8cm,compat=newest}
begin{document}
begin{tikzpicture}
begin{axis}[
xtick = empty, ytick = empty,
xlabel = {$x$},
x label style = {at={(1,0)},anchor=west},
ylabel = {$y$},
y label style = {at={(0,1)},rotate=-90,anchor=south},
axis lines=center,
enlargelimits=0.2,
]
addplot[color=red,smooth,thick,-] {(x)^2};
addplot[color=blue,mark=*,label={right:$P$}] (2,4);
addplot[mark=none, blue] coordinates {(-1,-2) (3,6)};
end{axis}
end{tikzpicture}
end{document}









share|improve this question




















  • 1





    The tangent to x^2 trhough (2,4) is y=4x-4.

    – Ignasi
    Nov 14 '17 at 9:44











  • question seems to be calculus problem :-)

    – Zarko
    Nov 14 '17 at 9:58






  • 1





    Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

    – Bobyandbob
    Nov 14 '17 at 12:48
















0















I want to draw the following diagram
enter image description here



Here is my MWE:



documentclass[border=3mm]{standalone}
usepackage{pgfplots}
pgfplotsset{width=8cm,compat=newest}
begin{document}
begin{tikzpicture}
begin{axis}[
xtick = empty, ytick = empty,
xlabel = {$x$},
x label style = {at={(1,0)},anchor=west},
ylabel = {$y$},
y label style = {at={(0,1)},rotate=-90,anchor=south},
axis lines=center,
enlargelimits=0.2,
]
addplot[color=red,smooth,thick,-] {(x)^2};
addplot[color=blue,mark=*,label={right:$P$}] (2,4);
addplot[mark=none, blue] coordinates {(-1,-2) (3,6)};
end{axis}
end{tikzpicture}
end{document}









share|improve this question




















  • 1





    The tangent to x^2 trhough (2,4) is y=4x-4.

    – Ignasi
    Nov 14 '17 at 9:44











  • question seems to be calculus problem :-)

    – Zarko
    Nov 14 '17 at 9:58






  • 1





    Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

    – Bobyandbob
    Nov 14 '17 at 12:48














0












0








0








I want to draw the following diagram
enter image description here



Here is my MWE:



documentclass[border=3mm]{standalone}
usepackage{pgfplots}
pgfplotsset{width=8cm,compat=newest}
begin{document}
begin{tikzpicture}
begin{axis}[
xtick = empty, ytick = empty,
xlabel = {$x$},
x label style = {at={(1,0)},anchor=west},
ylabel = {$y$},
y label style = {at={(0,1)},rotate=-90,anchor=south},
axis lines=center,
enlargelimits=0.2,
]
addplot[color=red,smooth,thick,-] {(x)^2};
addplot[color=blue,mark=*,label={right:$P$}] (2,4);
addplot[mark=none, blue] coordinates {(-1,-2) (3,6)};
end{axis}
end{tikzpicture}
end{document}









share|improve this question
















I want to draw the following diagram
enter image description here



Here is my MWE:



documentclass[border=3mm]{standalone}
usepackage{pgfplots}
pgfplotsset{width=8cm,compat=newest}
begin{document}
begin{tikzpicture}
begin{axis}[
xtick = empty, ytick = empty,
xlabel = {$x$},
x label style = {at={(1,0)},anchor=west},
ylabel = {$y$},
y label style = {at={(0,1)},rotate=-90,anchor=south},
axis lines=center,
enlargelimits=0.2,
]
addplot[color=red,smooth,thick,-] {(x)^2};
addplot[color=blue,mark=*,label={right:$P$}] (2,4);
addplot[mark=none, blue] coordinates {(-1,-2) (3,6)};
end{axis}
end{tikzpicture}
end{document}






tikz-pgf asymptote






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago









g.kov

17.6k14278




17.6k14278










asked Nov 14 '17 at 9:23









alboalbo

1327




1327








  • 1





    The tangent to x^2 trhough (2,4) is y=4x-4.

    – Ignasi
    Nov 14 '17 at 9:44











  • question seems to be calculus problem :-)

    – Zarko
    Nov 14 '17 at 9:58






  • 1





    Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

    – Bobyandbob
    Nov 14 '17 at 12:48














  • 1





    The tangent to x^2 trhough (2,4) is y=4x-4.

    – Ignasi
    Nov 14 '17 at 9:44











  • question seems to be calculus problem :-)

    – Zarko
    Nov 14 '17 at 9:58






  • 1





    Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

    – Bobyandbob
    Nov 14 '17 at 12:48








1




1





The tangent to x^2 trhough (2,4) is y=4x-4.

– Ignasi
Nov 14 '17 at 9:44





The tangent to x^2 trhough (2,4) is y=4x-4.

– Ignasi
Nov 14 '17 at 9:44













question seems to be calculus problem :-)

– Zarko
Nov 14 '17 at 9:58





question seems to be calculus problem :-)

– Zarko
Nov 14 '17 at 9:58




1




1





Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

– Bobyandbob
Nov 14 '17 at 12:48





Maybe how to graph general functions in latex could help (with x^2). - Related: [How to draw tangent line of an arbitrary point on a path in TikZ(tex.stackexchange.com/a/25940/124842)

– Bobyandbob
Nov 14 '17 at 12:48










3 Answers
3






active

oldest

votes


















2














Just for fun: pstricks-add has a psplotTangent command which accepts three arguments: the abscissa of the point of contact, the length of both sides of the tangent segment and the function:



documentclass[svgnames, x11names, border = 5pt]{standalone}%
usepackage[utf8]{inputenc}
usepackage{pstricks-add}%,
usepackage{pst-eucl, auto-pst-pdf}%

begin{document}

psset{xunit=2.2cm, yunit = 2cm, arrowinset = 0.12, algebraic, plotstyle = curve, plotpoints = 100}

begin{pspicture*}(-2,-1.2)(3,3)
psplot{-2}{2.7}{x^2}
uput[l](-1,1){$y = x^2$}
pstGeonode[PosAngle = {0,180}, PointName=](1,1){P}(1.6,2.56){Q}
uput[r](P){$P(1,1)$}uput[l](Q){$Q(x, x^2)$}
pstLineAB[linecolor = LightSteelBlue, nodesep = -5, showpoints]{P}{Q}
psplotTangent[linecolor = SkyBlue, showpoints]{1}{2.5}{x^2}
psaxes[linewidth = 0.6pt, labels = none, ticks = none, arrows = ->](0,0)(-2,-1.2)(3,3)[$x$, -110][$y$,210]
uput[dl](0,0){$0$}
end{pspicture*}

end{document}


enter image description here






share|improve this answer































    4














    Of course, it's better to have
    a functional expression for the tangent line,
    which in this example is a simple exercise.
    However, Asymptote offers a "calculus-free" way
    of drawing the tangent lines.
    There is
    a built-in function dir(path, time)
    exactly for this purpose.



    Let's pretend, that we don't know
    how to obtain the tangent line equation for the function.



    Given the function curve guide gf and x=1,
    we can use built-in function times



    t=times(gf,x)[0];


    to get a value of the time parameter t, which corresponds
    to the intersection of the function curve and a vertical line at x=1.
    This t value allows to: first,
    get a missing 'y' coordinate of the tangent point P



    P=point(gf,t);


    And second, the direction of the tangent line at this point
    as dir(gf,t).



    Function drawline
    (part of the basic Asymptote module math.asy),
    allows to draw the visible portion
    of the (infinite) line
    going through two points:



    drawline(P,P+dir(gf,t),tanLinePen);


    Another useful function for this drawing
    is relpoint, which
    returns the point on curve
    at the relative fraction of its arclength.



    This is a complete MWE:



    // tan.asy
    //
    // run
    // asy tan.asy
    //
    // to get tan.pdf
    //
    settings.tex="pdflatex";
    import graph; import math;
    size(6cm);
    import fontsize;defaultpen(fontsize(10pt));
    texpreamble("usepackage{lmodern}"
    +"usepackage{amsmath}"
    +"usepackage{amsfonts}"
    +"usepackage{amssymb}"
    );
    pen funcLinePen=darkblue+0.9bp;
    pen tanLinePen=orange+0.9bp;
    pen grayPen=gray(0.3)+0.8bp;
    pen dashPen=gray(0.3)+0.8bp+linetype(new real[]{5,5})+linecap(0);
    arrowbar arr=Arrow(HookHead,size=2);
    real xmin=-2,xmax=-xmin;
    real ymin=0,ymax=4;
    real dxmin=0.2;
    real dxmax=dxmin;
    real dymin=dxmin;
    real dymax=dxmax;

    add(shift(-2.5,-1)*scale(0.5)*grid(10,11,paleblue+0.3bp));

    xaxis("$x$",xmin-dxmin,xmax+dxmax,RightTicks(Step=1,step=0.5),arr,above=true);
    yaxis("$y$",ymin-dymin,ymax+dymax,LeftTicks (Step=1,step=0.5,OmitTick(0)),arr,above=true);

    real f(real x){return x^2;}

    guide gf=graph(f,xmin,xmax,operator..);

    real x=1, t=times(gf,x)[0];
    pair P=point(gf,t), Q=relpoint(gf,6/7);

    draw(gf,funcLinePen);
    draw((P.x,0)--P--(0,P.y),dashPen);
    drawline(P,P+dir(gf,t),tanLinePen);
    dot((P.x,0)^^P^^(0,P.y)^^Q,UnFill);
    label("$y=x^2$",relpoint(gf,1/4),UnFill);
    label("$P(1,"+string(round(P.y))+")$",P,plain.SE);
    label("$Q(x,x^2)$",Q,plain.W);
    label("$T$",Q,3*plain.E);


    enter image description here






    share|improve this answer































      2














      I'm surprised that the original question is tagged tikz-pgf but one answer (the accepted one) uses pstricks and the other uses asymptote! So I decide to post a TikZ answer, but this is mainly a mathematics answer.



      documentclass[tikz]{standalone}
      usetikzlibrary{through}
      begin{document}
      begin{tikzpicture}[declare function={f(x)=x*x;}]
      draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
      draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
      draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
      path (0,0) node[below left] {$0$};
      fill (1,{f(1)}) coordinate (p) circle (1pt);
      coordinate (x) at (0,{1/(4*f(1))});
      node[circle through={(p)}] (cir) at (x) {};
      draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
      end{tikzpicture}
      end{document}


      enter image description here



      This code works for any P on the parabola once the equation of the parabola is still in the form of ax2. For general case ax2 + bx + c, please edit the coordinate of (x)!



      documentclass[tikz]{standalone}
      usetikzlibrary{through}
      begin{document}
      begin{tikzpicture}[declare function={f(x)=2*x*x;}]
      draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
      draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
      draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
      path (0,0) node[below left] {$0$};
      fill (-.5,{f(-.5)}) coordinate (p) circle (1pt);
      coordinate (x) at (0,{1/(4*f(1))});
      node[circle through={(p)}] (cir) at (x) {};
      draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
      end{tikzpicture}
      end{document}


      enter image description here





      Proof of correctness



      I find the focus of the parabola, after that I can find another point on the tangent line.



      documentclass[tikz]{standalone}
      usetikzlibrary{through}
      begin{document}
      begin{tikzpicture}[declare function={f(x)=x*x;}]
      draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
      draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
      draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
      path (0,0) node[below left] {$0$};
      fill (1.2,{f(1.2)}) coordinate (p) circle (1pt);
      coordinate (x) at (0,{1/(4*f(1))});
      fill (x) circle (1pt);
      node[draw,very thin,dashed,circle through={(p)}] (cir) at (x) {};
      fill (cir.south) circle (1pt);
      draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
      end{tikzpicture}
      end{document}


      enter image description here






      share|improve this answer
























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        3 Answers
        3






        active

        oldest

        votes








        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

        votes






        active

        oldest

        votes









        2














        Just for fun: pstricks-add has a psplotTangent command which accepts three arguments: the abscissa of the point of contact, the length of both sides of the tangent segment and the function:



        documentclass[svgnames, x11names, border = 5pt]{standalone}%
        usepackage[utf8]{inputenc}
        usepackage{pstricks-add}%,
        usepackage{pst-eucl, auto-pst-pdf}%

        begin{document}

        psset{xunit=2.2cm, yunit = 2cm, arrowinset = 0.12, algebraic, plotstyle = curve, plotpoints = 100}

        begin{pspicture*}(-2,-1.2)(3,3)
        psplot{-2}{2.7}{x^2}
        uput[l](-1,1){$y = x^2$}
        pstGeonode[PosAngle = {0,180}, PointName=](1,1){P}(1.6,2.56){Q}
        uput[r](P){$P(1,1)$}uput[l](Q){$Q(x, x^2)$}
        pstLineAB[linecolor = LightSteelBlue, nodesep = -5, showpoints]{P}{Q}
        psplotTangent[linecolor = SkyBlue, showpoints]{1}{2.5}{x^2}
        psaxes[linewidth = 0.6pt, labels = none, ticks = none, arrows = ->](0,0)(-2,-1.2)(3,3)[$x$, -110][$y$,210]
        uput[dl](0,0){$0$}
        end{pspicture*}

        end{document}


        enter image description here






        share|improve this answer




























          2














          Just for fun: pstricks-add has a psplotTangent command which accepts three arguments: the abscissa of the point of contact, the length of both sides of the tangent segment and the function:



          documentclass[svgnames, x11names, border = 5pt]{standalone}%
          usepackage[utf8]{inputenc}
          usepackage{pstricks-add}%,
          usepackage{pst-eucl, auto-pst-pdf}%

          begin{document}

          psset{xunit=2.2cm, yunit = 2cm, arrowinset = 0.12, algebraic, plotstyle = curve, plotpoints = 100}

          begin{pspicture*}(-2,-1.2)(3,3)
          psplot{-2}{2.7}{x^2}
          uput[l](-1,1){$y = x^2$}
          pstGeonode[PosAngle = {0,180}, PointName=](1,1){P}(1.6,2.56){Q}
          uput[r](P){$P(1,1)$}uput[l](Q){$Q(x, x^2)$}
          pstLineAB[linecolor = LightSteelBlue, nodesep = -5, showpoints]{P}{Q}
          psplotTangent[linecolor = SkyBlue, showpoints]{1}{2.5}{x^2}
          psaxes[linewidth = 0.6pt, labels = none, ticks = none, arrows = ->](0,0)(-2,-1.2)(3,3)[$x$, -110][$y$,210]
          uput[dl](0,0){$0$}
          end{pspicture*}

          end{document}


          enter image description here






          share|improve this answer


























            2












            2








            2







            Just for fun: pstricks-add has a psplotTangent command which accepts three arguments: the abscissa of the point of contact, the length of both sides of the tangent segment and the function:



            documentclass[svgnames, x11names, border = 5pt]{standalone}%
            usepackage[utf8]{inputenc}
            usepackage{pstricks-add}%,
            usepackage{pst-eucl, auto-pst-pdf}%

            begin{document}

            psset{xunit=2.2cm, yunit = 2cm, arrowinset = 0.12, algebraic, plotstyle = curve, plotpoints = 100}

            begin{pspicture*}(-2,-1.2)(3,3)
            psplot{-2}{2.7}{x^2}
            uput[l](-1,1){$y = x^2$}
            pstGeonode[PosAngle = {0,180}, PointName=](1,1){P}(1.6,2.56){Q}
            uput[r](P){$P(1,1)$}uput[l](Q){$Q(x, x^2)$}
            pstLineAB[linecolor = LightSteelBlue, nodesep = -5, showpoints]{P}{Q}
            psplotTangent[linecolor = SkyBlue, showpoints]{1}{2.5}{x^2}
            psaxes[linewidth = 0.6pt, labels = none, ticks = none, arrows = ->](0,0)(-2,-1.2)(3,3)[$x$, -110][$y$,210]
            uput[dl](0,0){$0$}
            end{pspicture*}

            end{document}


            enter image description here






            share|improve this answer













            Just for fun: pstricks-add has a psplotTangent command which accepts three arguments: the abscissa of the point of contact, the length of both sides of the tangent segment and the function:



            documentclass[svgnames, x11names, border = 5pt]{standalone}%
            usepackage[utf8]{inputenc}
            usepackage{pstricks-add}%,
            usepackage{pst-eucl, auto-pst-pdf}%

            begin{document}

            psset{xunit=2.2cm, yunit = 2cm, arrowinset = 0.12, algebraic, plotstyle = curve, plotpoints = 100}

            begin{pspicture*}(-2,-1.2)(3,3)
            psplot{-2}{2.7}{x^2}
            uput[l](-1,1){$y = x^2$}
            pstGeonode[PosAngle = {0,180}, PointName=](1,1){P}(1.6,2.56){Q}
            uput[r](P){$P(1,1)$}uput[l](Q){$Q(x, x^2)$}
            pstLineAB[linecolor = LightSteelBlue, nodesep = -5, showpoints]{P}{Q}
            psplotTangent[linecolor = SkyBlue, showpoints]{1}{2.5}{x^2}
            psaxes[linewidth = 0.6pt, labels = none, ticks = none, arrows = ->](0,0)(-2,-1.2)(3,3)[$x$, -110][$y$,210]
            uput[dl](0,0){$0$}
            end{pspicture*}

            end{document}


            enter image description here







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 14 '17 at 12:14









            BernardBernard

            175k777207




            175k777207























                4














                Of course, it's better to have
                a functional expression for the tangent line,
                which in this example is a simple exercise.
                However, Asymptote offers a "calculus-free" way
                of drawing the tangent lines.
                There is
                a built-in function dir(path, time)
                exactly for this purpose.



                Let's pretend, that we don't know
                how to obtain the tangent line equation for the function.



                Given the function curve guide gf and x=1,
                we can use built-in function times



                t=times(gf,x)[0];


                to get a value of the time parameter t, which corresponds
                to the intersection of the function curve and a vertical line at x=1.
                This t value allows to: first,
                get a missing 'y' coordinate of the tangent point P



                P=point(gf,t);


                And second, the direction of the tangent line at this point
                as dir(gf,t).



                Function drawline
                (part of the basic Asymptote module math.asy),
                allows to draw the visible portion
                of the (infinite) line
                going through two points:



                drawline(P,P+dir(gf,t),tanLinePen);


                Another useful function for this drawing
                is relpoint, which
                returns the point on curve
                at the relative fraction of its arclength.



                This is a complete MWE:



                // tan.asy
                //
                // run
                // asy tan.asy
                //
                // to get tan.pdf
                //
                settings.tex="pdflatex";
                import graph; import math;
                size(6cm);
                import fontsize;defaultpen(fontsize(10pt));
                texpreamble("usepackage{lmodern}"
                +"usepackage{amsmath}"
                +"usepackage{amsfonts}"
                +"usepackage{amssymb}"
                );
                pen funcLinePen=darkblue+0.9bp;
                pen tanLinePen=orange+0.9bp;
                pen grayPen=gray(0.3)+0.8bp;
                pen dashPen=gray(0.3)+0.8bp+linetype(new real[]{5,5})+linecap(0);
                arrowbar arr=Arrow(HookHead,size=2);
                real xmin=-2,xmax=-xmin;
                real ymin=0,ymax=4;
                real dxmin=0.2;
                real dxmax=dxmin;
                real dymin=dxmin;
                real dymax=dxmax;

                add(shift(-2.5,-1)*scale(0.5)*grid(10,11,paleblue+0.3bp));

                xaxis("$x$",xmin-dxmin,xmax+dxmax,RightTicks(Step=1,step=0.5),arr,above=true);
                yaxis("$y$",ymin-dymin,ymax+dymax,LeftTicks (Step=1,step=0.5,OmitTick(0)),arr,above=true);

                real f(real x){return x^2;}

                guide gf=graph(f,xmin,xmax,operator..);

                real x=1, t=times(gf,x)[0];
                pair P=point(gf,t), Q=relpoint(gf,6/7);

                draw(gf,funcLinePen);
                draw((P.x,0)--P--(0,P.y),dashPen);
                drawline(P,P+dir(gf,t),tanLinePen);
                dot((P.x,0)^^P^^(0,P.y)^^Q,UnFill);
                label("$y=x^2$",relpoint(gf,1/4),UnFill);
                label("$P(1,"+string(round(P.y))+")$",P,plain.SE);
                label("$Q(x,x^2)$",Q,plain.W);
                label("$T$",Q,3*plain.E);


                enter image description here






                share|improve this answer




























                  4














                  Of course, it's better to have
                  a functional expression for the tangent line,
                  which in this example is a simple exercise.
                  However, Asymptote offers a "calculus-free" way
                  of drawing the tangent lines.
                  There is
                  a built-in function dir(path, time)
                  exactly for this purpose.



                  Let's pretend, that we don't know
                  how to obtain the tangent line equation for the function.



                  Given the function curve guide gf and x=1,
                  we can use built-in function times



                  t=times(gf,x)[0];


                  to get a value of the time parameter t, which corresponds
                  to the intersection of the function curve and a vertical line at x=1.
                  This t value allows to: first,
                  get a missing 'y' coordinate of the tangent point P



                  P=point(gf,t);


                  And second, the direction of the tangent line at this point
                  as dir(gf,t).



                  Function drawline
                  (part of the basic Asymptote module math.asy),
                  allows to draw the visible portion
                  of the (infinite) line
                  going through two points:



                  drawline(P,P+dir(gf,t),tanLinePen);


                  Another useful function for this drawing
                  is relpoint, which
                  returns the point on curve
                  at the relative fraction of its arclength.



                  This is a complete MWE:



                  // tan.asy
                  //
                  // run
                  // asy tan.asy
                  //
                  // to get tan.pdf
                  //
                  settings.tex="pdflatex";
                  import graph; import math;
                  size(6cm);
                  import fontsize;defaultpen(fontsize(10pt));
                  texpreamble("usepackage{lmodern}"
                  +"usepackage{amsmath}"
                  +"usepackage{amsfonts}"
                  +"usepackage{amssymb}"
                  );
                  pen funcLinePen=darkblue+0.9bp;
                  pen tanLinePen=orange+0.9bp;
                  pen grayPen=gray(0.3)+0.8bp;
                  pen dashPen=gray(0.3)+0.8bp+linetype(new real[]{5,5})+linecap(0);
                  arrowbar arr=Arrow(HookHead,size=2);
                  real xmin=-2,xmax=-xmin;
                  real ymin=0,ymax=4;
                  real dxmin=0.2;
                  real dxmax=dxmin;
                  real dymin=dxmin;
                  real dymax=dxmax;

                  add(shift(-2.5,-1)*scale(0.5)*grid(10,11,paleblue+0.3bp));

                  xaxis("$x$",xmin-dxmin,xmax+dxmax,RightTicks(Step=1,step=0.5),arr,above=true);
                  yaxis("$y$",ymin-dymin,ymax+dymax,LeftTicks (Step=1,step=0.5,OmitTick(0)),arr,above=true);

                  real f(real x){return x^2;}

                  guide gf=graph(f,xmin,xmax,operator..);

                  real x=1, t=times(gf,x)[0];
                  pair P=point(gf,t), Q=relpoint(gf,6/7);

                  draw(gf,funcLinePen);
                  draw((P.x,0)--P--(0,P.y),dashPen);
                  drawline(P,P+dir(gf,t),tanLinePen);
                  dot((P.x,0)^^P^^(0,P.y)^^Q,UnFill);
                  label("$y=x^2$",relpoint(gf,1/4),UnFill);
                  label("$P(1,"+string(round(P.y))+")$",P,plain.SE);
                  label("$Q(x,x^2)$",Q,plain.W);
                  label("$T$",Q,3*plain.E);


                  enter image description here






                  share|improve this answer


























                    4












                    4








                    4







                    Of course, it's better to have
                    a functional expression for the tangent line,
                    which in this example is a simple exercise.
                    However, Asymptote offers a "calculus-free" way
                    of drawing the tangent lines.
                    There is
                    a built-in function dir(path, time)
                    exactly for this purpose.



                    Let's pretend, that we don't know
                    how to obtain the tangent line equation for the function.



                    Given the function curve guide gf and x=1,
                    we can use built-in function times



                    t=times(gf,x)[0];


                    to get a value of the time parameter t, which corresponds
                    to the intersection of the function curve and a vertical line at x=1.
                    This t value allows to: first,
                    get a missing 'y' coordinate of the tangent point P



                    P=point(gf,t);


                    And second, the direction of the tangent line at this point
                    as dir(gf,t).



                    Function drawline
                    (part of the basic Asymptote module math.asy),
                    allows to draw the visible portion
                    of the (infinite) line
                    going through two points:



                    drawline(P,P+dir(gf,t),tanLinePen);


                    Another useful function for this drawing
                    is relpoint, which
                    returns the point on curve
                    at the relative fraction of its arclength.



                    This is a complete MWE:



                    // tan.asy
                    //
                    // run
                    // asy tan.asy
                    //
                    // to get tan.pdf
                    //
                    settings.tex="pdflatex";
                    import graph; import math;
                    size(6cm);
                    import fontsize;defaultpen(fontsize(10pt));
                    texpreamble("usepackage{lmodern}"
                    +"usepackage{amsmath}"
                    +"usepackage{amsfonts}"
                    +"usepackage{amssymb}"
                    );
                    pen funcLinePen=darkblue+0.9bp;
                    pen tanLinePen=orange+0.9bp;
                    pen grayPen=gray(0.3)+0.8bp;
                    pen dashPen=gray(0.3)+0.8bp+linetype(new real[]{5,5})+linecap(0);
                    arrowbar arr=Arrow(HookHead,size=2);
                    real xmin=-2,xmax=-xmin;
                    real ymin=0,ymax=4;
                    real dxmin=0.2;
                    real dxmax=dxmin;
                    real dymin=dxmin;
                    real dymax=dxmax;

                    add(shift(-2.5,-1)*scale(0.5)*grid(10,11,paleblue+0.3bp));

                    xaxis("$x$",xmin-dxmin,xmax+dxmax,RightTicks(Step=1,step=0.5),arr,above=true);
                    yaxis("$y$",ymin-dymin,ymax+dymax,LeftTicks (Step=1,step=0.5,OmitTick(0)),arr,above=true);

                    real f(real x){return x^2;}

                    guide gf=graph(f,xmin,xmax,operator..);

                    real x=1, t=times(gf,x)[0];
                    pair P=point(gf,t), Q=relpoint(gf,6/7);

                    draw(gf,funcLinePen);
                    draw((P.x,0)--P--(0,P.y),dashPen);
                    drawline(P,P+dir(gf,t),tanLinePen);
                    dot((P.x,0)^^P^^(0,P.y)^^Q,UnFill);
                    label("$y=x^2$",relpoint(gf,1/4),UnFill);
                    label("$P(1,"+string(round(P.y))+")$",P,plain.SE);
                    label("$Q(x,x^2)$",Q,plain.W);
                    label("$T$",Q,3*plain.E);


                    enter image description here






                    share|improve this answer













                    Of course, it's better to have
                    a functional expression for the tangent line,
                    which in this example is a simple exercise.
                    However, Asymptote offers a "calculus-free" way
                    of drawing the tangent lines.
                    There is
                    a built-in function dir(path, time)
                    exactly for this purpose.



                    Let's pretend, that we don't know
                    how to obtain the tangent line equation for the function.



                    Given the function curve guide gf and x=1,
                    we can use built-in function times



                    t=times(gf,x)[0];


                    to get a value of the time parameter t, which corresponds
                    to the intersection of the function curve and a vertical line at x=1.
                    This t value allows to: first,
                    get a missing 'y' coordinate of the tangent point P



                    P=point(gf,t);


                    And second, the direction of the tangent line at this point
                    as dir(gf,t).



                    Function drawline
                    (part of the basic Asymptote module math.asy),
                    allows to draw the visible portion
                    of the (infinite) line
                    going through two points:



                    drawline(P,P+dir(gf,t),tanLinePen);


                    Another useful function for this drawing
                    is relpoint, which
                    returns the point on curve
                    at the relative fraction of its arclength.



                    This is a complete MWE:



                    // tan.asy
                    //
                    // run
                    // asy tan.asy
                    //
                    // to get tan.pdf
                    //
                    settings.tex="pdflatex";
                    import graph; import math;
                    size(6cm);
                    import fontsize;defaultpen(fontsize(10pt));
                    texpreamble("usepackage{lmodern}"
                    +"usepackage{amsmath}"
                    +"usepackage{amsfonts}"
                    +"usepackage{amssymb}"
                    );
                    pen funcLinePen=darkblue+0.9bp;
                    pen tanLinePen=orange+0.9bp;
                    pen grayPen=gray(0.3)+0.8bp;
                    pen dashPen=gray(0.3)+0.8bp+linetype(new real[]{5,5})+linecap(0);
                    arrowbar arr=Arrow(HookHead,size=2);
                    real xmin=-2,xmax=-xmin;
                    real ymin=0,ymax=4;
                    real dxmin=0.2;
                    real dxmax=dxmin;
                    real dymin=dxmin;
                    real dymax=dxmax;

                    add(shift(-2.5,-1)*scale(0.5)*grid(10,11,paleblue+0.3bp));

                    xaxis("$x$",xmin-dxmin,xmax+dxmax,RightTicks(Step=1,step=0.5),arr,above=true);
                    yaxis("$y$",ymin-dymin,ymax+dymax,LeftTicks (Step=1,step=0.5,OmitTick(0)),arr,above=true);

                    real f(real x){return x^2;}

                    guide gf=graph(f,xmin,xmax,operator..);

                    real x=1, t=times(gf,x)[0];
                    pair P=point(gf,t), Q=relpoint(gf,6/7);

                    draw(gf,funcLinePen);
                    draw((P.x,0)--P--(0,P.y),dashPen);
                    drawline(P,P+dir(gf,t),tanLinePen);
                    dot((P.x,0)^^P^^(0,P.y)^^Q,UnFill);
                    label("$y=x^2$",relpoint(gf,1/4),UnFill);
                    label("$P(1,"+string(round(P.y))+")$",P,plain.SE);
                    label("$Q(x,x^2)$",Q,plain.W);
                    label("$T$",Q,3*plain.E);


                    enter image description here







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 14 '17 at 17:04









                    g.kovg.kov

                    17.6k14278




                    17.6k14278























                        2














                        I'm surprised that the original question is tagged tikz-pgf but one answer (the accepted one) uses pstricks and the other uses asymptote! So I decide to post a TikZ answer, but this is mainly a mathematics answer.



                        documentclass[tikz]{standalone}
                        usetikzlibrary{through}
                        begin{document}
                        begin{tikzpicture}[declare function={f(x)=x*x;}]
                        draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                        draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                        draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                        path (0,0) node[below left] {$0$};
                        fill (1,{f(1)}) coordinate (p) circle (1pt);
                        coordinate (x) at (0,{1/(4*f(1))});
                        node[circle through={(p)}] (cir) at (x) {};
                        draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                        end{tikzpicture}
                        end{document}


                        enter image description here



                        This code works for any P on the parabola once the equation of the parabola is still in the form of ax2. For general case ax2 + bx + c, please edit the coordinate of (x)!



                        documentclass[tikz]{standalone}
                        usetikzlibrary{through}
                        begin{document}
                        begin{tikzpicture}[declare function={f(x)=2*x*x;}]
                        draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                        draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                        draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                        path (0,0) node[below left] {$0$};
                        fill (-.5,{f(-.5)}) coordinate (p) circle (1pt);
                        coordinate (x) at (0,{1/(4*f(1))});
                        node[circle through={(p)}] (cir) at (x) {};
                        draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                        end{tikzpicture}
                        end{document}


                        enter image description here





                        Proof of correctness



                        I find the focus of the parabola, after that I can find another point on the tangent line.



                        documentclass[tikz]{standalone}
                        usetikzlibrary{through}
                        begin{document}
                        begin{tikzpicture}[declare function={f(x)=x*x;}]
                        draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                        draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                        draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                        path (0,0) node[below left] {$0$};
                        fill (1.2,{f(1.2)}) coordinate (p) circle (1pt);
                        coordinate (x) at (0,{1/(4*f(1))});
                        fill (x) circle (1pt);
                        node[draw,very thin,dashed,circle through={(p)}] (cir) at (x) {};
                        fill (cir.south) circle (1pt);
                        draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                        end{tikzpicture}
                        end{document}


                        enter image description here






                        share|improve this answer




























                          2














                          I'm surprised that the original question is tagged tikz-pgf but one answer (the accepted one) uses pstricks and the other uses asymptote! So I decide to post a TikZ answer, but this is mainly a mathematics answer.



                          documentclass[tikz]{standalone}
                          usetikzlibrary{through}
                          begin{document}
                          begin{tikzpicture}[declare function={f(x)=x*x;}]
                          draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                          draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                          draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                          path (0,0) node[below left] {$0$};
                          fill (1,{f(1)}) coordinate (p) circle (1pt);
                          coordinate (x) at (0,{1/(4*f(1))});
                          node[circle through={(p)}] (cir) at (x) {};
                          draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                          end{tikzpicture}
                          end{document}


                          enter image description here



                          This code works for any P on the parabola once the equation of the parabola is still in the form of ax2. For general case ax2 + bx + c, please edit the coordinate of (x)!



                          documentclass[tikz]{standalone}
                          usetikzlibrary{through}
                          begin{document}
                          begin{tikzpicture}[declare function={f(x)=2*x*x;}]
                          draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                          draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                          draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                          path (0,0) node[below left] {$0$};
                          fill (-.5,{f(-.5)}) coordinate (p) circle (1pt);
                          coordinate (x) at (0,{1/(4*f(1))});
                          node[circle through={(p)}] (cir) at (x) {};
                          draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                          end{tikzpicture}
                          end{document}


                          enter image description here





                          Proof of correctness



                          I find the focus of the parabola, after that I can find another point on the tangent line.



                          documentclass[tikz]{standalone}
                          usetikzlibrary{through}
                          begin{document}
                          begin{tikzpicture}[declare function={f(x)=x*x;}]
                          draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                          draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                          draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                          path (0,0) node[below left] {$0$};
                          fill (1.2,{f(1.2)}) coordinate (p) circle (1pt);
                          coordinate (x) at (0,{1/(4*f(1))});
                          fill (x) circle (1pt);
                          node[draw,very thin,dashed,circle through={(p)}] (cir) at (x) {};
                          fill (cir.south) circle (1pt);
                          draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                          end{tikzpicture}
                          end{document}


                          enter image description here






                          share|improve this answer


























                            2












                            2








                            2







                            I'm surprised that the original question is tagged tikz-pgf but one answer (the accepted one) uses pstricks and the other uses asymptote! So I decide to post a TikZ answer, but this is mainly a mathematics answer.



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (1,{f(1)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            node[circle through={(p)}] (cir) at (x) {};
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here



                            This code works for any P on the parabola once the equation of the parabola is still in the form of ax2. For general case ax2 + bx + c, please edit the coordinate of (x)!



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=2*x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (-.5,{f(-.5)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            node[circle through={(p)}] (cir) at (x) {};
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here





                            Proof of correctness



                            I find the focus of the parabola, after that I can find another point on the tangent line.



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (1.2,{f(1.2)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            fill (x) circle (1pt);
                            node[draw,very thin,dashed,circle through={(p)}] (cir) at (x) {};
                            fill (cir.south) circle (1pt);
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here






                            share|improve this answer













                            I'm surprised that the original question is tagged tikz-pgf but one answer (the accepted one) uses pstricks and the other uses asymptote! So I decide to post a TikZ answer, but this is mainly a mathematics answer.



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (1,{f(1)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            node[circle through={(p)}] (cir) at (x) {};
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here



                            This code works for any P on the parabola once the equation of the parabola is still in the form of ax2. For general case ax2 + bx + c, please edit the coordinate of (x)!



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=2*x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (-.5,{f(-.5)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            node[circle through={(p)}] (cir) at (x) {};
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here





                            Proof of correctness



                            I find the focus of the parabola, after that I can find another point on the tangent line.



                            documentclass[tikz]{standalone}
                            usetikzlibrary{through}
                            begin{document}
                            begin{tikzpicture}[declare function={f(x)=x*x;}]
                            draw[-latex] (-2.5,0)--(2.5,0) node[below] {$x$};
                            draw[-latex] (0,-2)--(0,2.5) node[left] {$y$};
                            draw plot[smooth,samples=100,domain=-1.5:1.5] (x,{f(x)});
                            path (0,0) node[below left] {$0$};
                            fill (1.2,{f(1.2)}) coordinate (p) circle (1pt);
                            coordinate (x) at (0,{1/(4*f(1))});
                            fill (x) circle (1pt);
                            node[draw,very thin,dashed,circle through={(p)}] (cir) at (x) {};
                            fill (cir.south) circle (1pt);
                            draw[shorten >=-1.5cm,shorten <=-1cm] (cir.south)--(p);
                            end{tikzpicture}
                            end{document}


                            enter image description here







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 7 hours ago









                            JouleVJouleV

                            10.8k22560




                            10.8k22560






























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