Size problems when plotting xy/(x^2+2y^2)Omitting a range when plotting with pgfplotsDisplay problems when...
Do "fields" always combine by addition?
What is the difference between "...", '...', $'...', and $"..." quotes?
Is a new boolean field better than null reference when a value can be meaningfully absent?
Am I a Rude Number?
Why are all my replica super soldiers young adults or old teenagers?
Non-Cancer terminal illness that can affect young (age 10-13) girls?
Identify KNO3 and KH2PO4 at home
Square Root Distance from Integers
After checking in online, how do I know whether I need to go show my passport at airport check-in?
Why does photorec keep finding files after I have filled the disk free space as root?
TikZ graph edges not drawn nicely
Boss asked me to sign a resignation paper without a date on it along with my new contract
How does Leonard in "Memento" remember reading and writing?
Limits of a density function
Play Zip, Zap, Zop
Globe trotting Grandpa. Where is he going next?
Potential client has a problematic employee I can't work with
Is there a defined priority for pattern matching?
Why are the books in the Game of Thrones citadel library shelved spine inwards?
Custom color for fence, whisker and outliers in BoxWhiskerChart
Should I reinstall Linux when changing the laptop's CPU?
Hilchos Shabbos English Sefer
Why is Agricola named as such?
Looking for a specific 6502 Assembler
Size problems when plotting xy/(x^2+2y^2)
Omitting a range when plotting with pgfplotsDisplay problems when plotting large datasets (unwanted spikes)Problems plotting histograms as a line graph?How to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Mysterious dash when plotting TikZProblems at Plotting the function in 3d SystemProblems with plotting planar functions with Tikzcreate a standalone legend for a grid of plotsStrange asymmetry when plotting identical exponents?Difficulties (unexplained error message) when plotting contour
I would like to plot the funtion xy/(x^2+2y^2) using PGFPlots. Here is what I want:
Please consider this MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{amssymb}
usepackage{amsmath}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]
begin{axis} [
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};;
end{axis}
end{tikzpicture}
end{center}
end{document}
The MWE output has an incredible big zoom, so I would like to resize the plot but not using scale but another commands, like enlarge limits. However, all the results are in vain; I can not reproduce the visual appearance of what I want.
Thanks!!
tikz-pgf
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
This question has an open bounty worth +50
reputation from manooooh ending in 7 days.
One or more of the answers is exemplary and worthy of an additional bounty.
marmot is one of the best users.
|
show 5 more comments
I would like to plot the funtion xy/(x^2+2y^2) using PGFPlots. Here is what I want:
Please consider this MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{amssymb}
usepackage{amsmath}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]
begin{axis} [
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};;
end{axis}
end{tikzpicture}
end{center}
end{document}
The MWE output has an incredible big zoom, so I would like to resize the plot but not using scale but another commands, like enlarge limits. However, all the results are in vain; I can not reproduce the visual appearance of what I want.
Thanks!!
tikz-pgf
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
This question has an open bounty worth +50
reputation from manooooh ending in 7 days.
One or more of the answers is exemplary and worthy of an additional bounty.
marmot is one of the best users.
1
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,x=r cos(phi)andy=r sin(phi), you see that the function does not depend onrbut only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.
– marmot
Feb 24 at 7:02
@marmot please see the edit. The function has a "normal" behaviour when changingdomain y=-1.2:1todomain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?
– manooooh
Feb 24 at 7:05
1
Normally you can setwidth=15cmor something like this. Of course, withaxis equal image,one needs to be a bit careful. What I meant to say is that the function is not well-defined atx=y=0and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.
– marmot
Feb 24 at 7:11
1
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
1
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45
|
show 5 more comments
I would like to plot the funtion xy/(x^2+2y^2) using PGFPlots. Here is what I want:
Please consider this MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{amssymb}
usepackage{amsmath}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]
begin{axis} [
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};;
end{axis}
end{tikzpicture}
end{center}
end{document}
The MWE output has an incredible big zoom, so I would like to resize the plot but not using scale but another commands, like enlarge limits. However, all the results are in vain; I can not reproduce the visual appearance of what I want.
Thanks!!
tikz-pgf
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
I would like to plot the funtion xy/(x^2+2y^2) using PGFPlots. Here is what I want:
Please consider this MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{amssymb}
usepackage{amsmath}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);}]
begin{axis} [
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-1:1,domain y=-1:1,samples=61, samples y=61] {f(x,y)};;
end{axis}
end{tikzpicture}
end{center}
end{document}
The MWE output has an incredible big zoom, so I would like to resize the plot but not using scale but another commands, like enlarge limits. However, all the results are in vain; I can not reproduce the visual appearance of what I want.
Thanks!!
tikz-pgf
tikz-pgf
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
edited Feb 24 at 7:57
manooooh
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
asked Feb 24 at 6:34
manoooohmanooooh
1,1061516
1,1061516
This question has an open bounty worth +50
reputation from manooooh ending in 7 days.
One or more of the answers is exemplary and worthy of an additional bounty.
marmot is one of the best users.
This question has an open bounty worth +50
reputation from manooooh ending in 7 days.
One or more of the answers is exemplary and worthy of an additional bounty.
marmot is one of the best users.
1
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,x=r cos(phi)andy=r sin(phi), you see that the function does not depend onrbut only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.
– marmot
Feb 24 at 7:02
@marmot please see the edit. The function has a "normal" behaviour when changingdomain y=-1.2:1todomain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?
– manooooh
Feb 24 at 7:05
1
Normally you can setwidth=15cmor something like this. Of course, withaxis equal image,one needs to be a bit careful. What I meant to say is that the function is not well-defined atx=y=0and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.
– marmot
Feb 24 at 7:11
1
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
1
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45
|
show 5 more comments
1
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,x=r cos(phi)andy=r sin(phi), you see that the function does not depend onrbut only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.
– marmot
Feb 24 at 7:02
@marmot please see the edit. The function has a "normal" behaviour when changingdomain y=-1.2:1todomain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?
– manooooh
Feb 24 at 7:05
1
Normally you can setwidth=15cmor something like this. Of course, withaxis equal image,one needs to be a bit careful. What I meant to say is that the function is not well-defined atx=y=0and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.
– marmot
Feb 24 at 7:11
1
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
1
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45
1
1
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,
x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.– marmot
Feb 24 at 7:02
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,
x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.– marmot
Feb 24 at 7:02
@marmot please see the edit. The function has a "normal" behaviour when changing
domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?– manooooh
Feb 24 at 7:05
@marmot please see the edit. The function has a "normal" behaviour when changing
domain y=-1.2:1 to domain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?– manooooh
Feb 24 at 7:05
1
1
Normally you can set
width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.– marmot
Feb 24 at 7:11
Normally you can set
width=15cm or something like this. Of course, with axis equal image, one needs to be a bit careful. What I meant to say is that the function is not well-defined at x=y=0 and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.– marmot
Feb 24 at 7:11
1
1
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
1
1
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45
|
show 5 more comments
1 Answer
1
active
oldest
votes
Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{document}
begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis}
addplot[domain=0:360,smooth,samples=101] {fan(x)};
end{axis}
end{tikzpicture}
end{document}
And this yields a 3d smooth plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);
fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis} [width=18cm,
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
data cs=polar,
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:360,
domain y=0:1,samples=61, samples y=21,
z buffer=sort] { fan(x)};
addlegendentry{{$f(x,y)$}}
end{axis}
end{tikzpicture}
end{document}
answered Feb 24 at 7:29
marmotmarmot
104k4123234
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f476422%2fsize-problems-when-plotting-xy-x22y2%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{document}
begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis}
addplot[domain=0:360,smooth,samples=101] {fan(x)};
end{axis}
end{tikzpicture}
end{document}
And this yields a 3d smooth plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);
fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis} [width=18cm,
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
data cs=polar,
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:360,
domain y=0:1,samples=61, samples y=21,
z buffer=sort] { fan(x)};
addlegendentry{{$f(x,y)$}}
end{axis}
end{tikzpicture}
end{document}
answered Feb 24 at 7:29
marmotmarmot
104k4123234
add a comment |
Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{document}
begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis}
addplot[domain=0:360,smooth,samples=101] {fan(x)};
end{axis}
end{tikzpicture}
end{document}
And this yields a 3d smooth plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);
fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis} [width=18cm,
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
data cs=polar,
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:360,
domain y=0:1,samples=61, samples y=21,
z buffer=sort] { fan(x)};
addlegendentry{{$f(x,y)$}}
end{axis}
end{tikzpicture}
end{document}
answered Feb 24 at 7:29
marmotmarmot
104k4123234
add a comment |
Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{document}
begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis}
addplot[domain=0:360,smooth,samples=101] {fan(x)};
end{axis}
end{tikzpicture}
end{document}
And this yields a 3d smooth plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);
fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis} [width=18cm,
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
data cs=polar,
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:360,
domain y=0:1,samples=61, samples y=21,
z buffer=sort] { fan(x)};
addlegendentry{{$f(x,y)$}}
end{axis}
end{tikzpicture}
end{document}
answered Feb 24 at 7:29
marmotmarmot
104k4123234
Not an answer to the (LaTeX part of the) question. However, if you use polar coordinates in the x-y plane, x=r cos(phi) and y=r sin(phi), you see that the function does not depend on r but only on the angle. So away from the origin x=y=0 all the information is already in a one-dimensional plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{document}
begin{tikzpicture}[declare function={fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis}
addplot[domain=0:360,smooth,samples=101] {fan(x)};
end{axis}
end{tikzpicture}
end{document}
And this yields a 3d smooth plot.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{tikzpicture}[declare function={f(x,y)=(x*y)/(x*x+2*y*y);
fan(t)=-(sin(2*t)/(-3 + cos(2*t)));}]
begin{axis} [width=18cm,
axis on top,
axis equal image,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
zmin=-1,
zmax=1,
ztick={-1,0,0.33,1},
zticklabels={$-1$,$0$,$1/3$,$1$},
ticklabel style={font=tiny},
legend pos=outer north east,
legend style={cells={align=left}},
legend cell align={left},
view={-135}{25},
data cs=polar,
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:360,
domain y=0:1,samples=61, samples y=21,
z buffer=sort] { fan(x)};
addlegendentry{{$f(x,y)$}}
end{axis}
end{tikzpicture}
end{document}
answered Feb 24 at 7:29
marmotmarmot
104k4123234
edited 2 days ago
answered Feb 24 at 7:29
marmotmarmot
104k4123234
answered Feb 24 at 7:29
marmotmarmot
104k4123234
answered Feb 24 at 7:29
marmotmarmot
104k4123234
104k4123234
add a comment |
add a comment |
Thanks for contributing an answer to TeX - LaTeX Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f476422%2fsize-problems-when-plotting-xy-x22y2%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Are you sure you want to plot the function in this way? If you use polar coordinates in the x-y plane,
x=r cos(phi)andy=r sin(phi), you see that the function does not depend onrbut only on the angle. This explains the behavior at 0, where the function is not well-defined. And otherwise the function depends only on one variable, so I am wondering if you would be better off if you plotted a function of one variable only, or at least use a different parametrization.– marmot
Feb 24 at 7:02
@marmot please see the edit. The function has a "normal" behaviour when changing
domain y=-1.2:1todomain y=-1:1. If you want to use change of variables go ahead :). Do you know how to "enlarge" the axis without rescaling the entire function in order to make it a little more bigger?– manooooh
Feb 24 at 7:05
1
Normally you can set
width=15cmor something like this. Of course, withaxis equal image,one needs to be a bit careful. What I meant to say is that the function is not well-defined atx=y=0and otherwise only a function that depends on one variable, not on two. You see this actually rather well in the upper plot.– marmot
Feb 24 at 7:11
1
I need to sleep so I will just post some 1d plot.
– marmot
Feb 24 at 7:28
1
Please do not alter the question that essentially by editing. It is much better to ask a new question.
– TeXnician
Feb 24 at 7:45