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Count number of li element and addclass
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I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
add a comment |
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
11 mins ago
add a comment |
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
javascript html css
javascript html css
asked 1 hour ago
kk kkkk kk
926
926
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
11 mins ago
add a comment |
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
44 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
11 mins ago
1
1
Your
$(this)
is not pointing to .box2
as you expect– Mr. Alien
1 hour ago
Your
$(this)
is not pointing to .box2
as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no .box1
after it.– LGSon
49 mins ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no .box1
after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this)
shows that $(this)
is pointing to .box2
. If you reverse the HTML structure of box1
and box2
and change the JavaScript
to return 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start of find
.– Andy Hoffman
44 mins ago
@Mr.Alien A
console.log($(this)
shows that $(this)
is pointing to .box2
. If you reverse the HTML structure of box1
and box2
and change the JavaScript
to return 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start of find
.– Andy Hoffman
44 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
11 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
11 mins ago
add a comment |
5 Answers
5
active
oldest
votes
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 1 hour ago
answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 1 hour ago
answered 1 hour ago
brkbrk
28.4k32143
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 55 mins ago
answered 1 hour ago
MamunMamun
29k71831
29k71831
add a comment |
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 21 mins ago
answered 1 hour ago
ellipsisellipsis
7,6962929
7,6962929
add a comment |
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
1169
add a comment |
add a comment |
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1
Your
$(this)
is not pointing to.box2
as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no.box1
after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.– Andy Hoffman
44 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
11 mins ago