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Find a good view for a function by parts using tikzpicture environment
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1
I want to plot sqrt(-xy) if xy<=0, and -x^2+y if xy>0.
Please consider this MWE:
documentclass{article}
usepackage[utf8]{inputenc}
usepackage{pgfplots}
pgfplotsset{compat=1.8}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[scale=2]
begin{axis}[
legend pos=outer north east,
axis lines = center,
view={-35}{15},
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
zticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
zlabel = $z$,
legend style={cells={align=left}}
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:-3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:3,samples=40, samples y=20] {-x*x+y};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:-3,samples=40, samples y=20] {-x*x+y};
end{axis}
end{tikzpicture}
end{center}
end{document}
I cannot find a good view for display the function. I think I like the view from the x<0 and y<0 but it is the image and it is ugly. What do you recommend not using gnuplot?
Thanks!
EDIT. I also would like to graph 7 vectors with norm 1: 4 in the xy-plane, and 3 in the direction of x>0 and y>0. i.e.:
in 3D. If it is complicated to see, you can do it in 2D, like the image.
tikz-pgf
edited 13 mins ago
Phelype Oleinik
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
add a comment |
1
I want to plot sqrt(-xy) if xy<=0, and -x^2+y if xy>0.
Please consider this MWE:
documentclass{article}
usepackage[utf8]{inputenc}
usepackage{pgfplots}
pgfplotsset{compat=1.8}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[scale=2]
begin{axis}[
legend pos=outer north east,
axis lines = center,
view={-35}{15},
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
zticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
zlabel = $z$,
legend style={cells={align=left}}
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:-3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:3,samples=40, samples y=20] {-x*x+y};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:-3,samples=40, samples y=20] {-x*x+y};
end{axis}
end{tikzpicture}
end{center}
end{document}
I cannot find a good view for display the function. I think I like the view from the x<0 and y<0 but it is the image and it is ugly. What do you recommend not using gnuplot?
Thanks!
EDIT. I also would like to graph 7 vectors with norm 1: 4 in the xy-plane, and 3 in the direction of x>0 and y>0. i.e.:
in 3D. If it is complicated to see, you can do it in 2D, like the image.
tikz-pgf
edited 13 mins ago
Phelype Oleinik
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
Probably we should do something with the graph atx>0andy>0(where the function is-x^2+y) because it is the ugliest part.
– manooooh
Oct 26 '18 at 23:28
1
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
@marmot if possible, I want to graph the7vectors with norm1in3D. That's probably bad (very bad), so the vectors in2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.
– manooooh
Oct 27 '18 at 1:19
add a comment |
1
1
1
I want to plot sqrt(-xy) if xy<=0, and -x^2+y if xy>0.
Please consider this MWE:
documentclass{article}
usepackage[utf8]{inputenc}
usepackage{pgfplots}
pgfplotsset{compat=1.8}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[scale=2]
begin{axis}[
legend pos=outer north east,
axis lines = center,
view={-35}{15},
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
zticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
zlabel = $z$,
legend style={cells={align=left}}
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:-3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:3,samples=40, samples y=20] {-x*x+y};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:-3,samples=40, samples y=20] {-x*x+y};
end{axis}
end{tikzpicture}
end{center}
end{document}
I cannot find a good view for display the function. I think I like the view from the x<0 and y<0 but it is the image and it is ugly. What do you recommend not using gnuplot?
Thanks!
EDIT. I also would like to graph 7 vectors with norm 1: 4 in the xy-plane, and 3 in the direction of x>0 and y>0. i.e.:
in 3D. If it is complicated to see, you can do it in 2D, like the image.
tikz-pgf
edited 13 mins ago
Phelype Oleinik
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
I want to plot sqrt(-xy) if xy<=0, and -x^2+y if xy>0.
Please consider this MWE:
documentclass{article}
usepackage[utf8]{inputenc}
usepackage{pgfplots}
pgfplotsset{compat=1.8}
pgfplotsset{soldot/.style={color=black,only marks,mark=*}}
pgfplotsset{holdot/.style={color=red,fill=white,very thick,only marks,mark=*}}
begin{document}
begin{center}
begin{tikzpicture}[scale=2]
begin{axis}[
legend pos=outer north east,
axis lines = center,
view={-35}{15},
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
zticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
zlabel = $z$,
legend style={cells={align=left}}
]
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:-3,samples=40, samples y=20] {sqrt(-x*y)};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=0:3,domain y=0:3,samples=40, samples y=20] {-x*x+y};
addplot3[surf,mesh/ordering=y varies,shader=interp,domain=-3:0,domain y=0:-3,samples=40, samples y=20] {-x*x+y};
end{axis}
end{tikzpicture}
end{center}
end{document}
I cannot find a good view for display the function. I think I like the view from the x<0 and y<0 but it is the image and it is ugly. What do you recommend not using gnuplot?
Thanks!
EDIT. I also would like to graph 7 vectors with norm 1: 4 in the xy-plane, and 3 in the direction of x>0 and y>0. i.e.:
in 3D. If it is complicated to see, you can do it in 2D, like the image.
tikz-pgf
tikz-pgf
edited 13 mins ago
Phelype Oleinik
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
edited 13 mins ago
Phelype Oleinik
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
edited 13 mins ago
Phelype Oleinik
23.6k54586
edited 13 mins ago
Phelype Oleinik
23.6k54586
edited 13 mins ago
Phelype Oleinik
23.6k54586
23.6k54586
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
asked Oct 26 '18 at 23:14
manoooohmanooooh
1,1291516
1,1291516
Probably we should do something with the graph atx>0andy>0(where the function is-x^2+y) because it is the ugliest part.
– manooooh
Oct 26 '18 at 23:28
1
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
@marmot if possible, I want to graph the7vectors with norm1in3D. That's probably bad (very bad), so the vectors in2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.
– manooooh
Oct 27 '18 at 1:19
add a comment |
Probably we should do something with the graph atx>0andy>0(where the function is-x^2+y) because it is the ugliest part.
– manooooh
Oct 26 '18 at 23:28
1
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
@marmot if possible, I want to graph the7vectors with norm1in3D. That's probably bad (very bad), so the vectors in2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.
– manooooh
Oct 27 '18 at 1:19
Probably we should do something with the graph at
x>0 and y>0 (where the function is -x^2+y) because it is the ugliest part.– manooooh
Oct 26 '18 at 23:28
Probably we should do something with the graph at
x>0 and y>0 (where the function is -x^2+y) because it is the ugliest part.– manooooh
Oct 26 '18 at 23:28
1
1
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
@marmot if possible, I want to graph the
7 vectors with norm 1 in 3D. That's probably bad (very bad), so the vectors in 2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.– manooooh
Oct 27 '18 at 1:19
@marmot if possible, I want to graph the
7 vectors with norm 1 in 3D. That's probably bad (very bad), so the vectors in 2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.– manooooh
Oct 27 '18 at 1:19
add a comment |
1 Answer
1
active
oldest
votes
2
Here's a proposal. Draw the axes by hand and hide what you have to hide.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={75}{45},clip=false
]
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[right]{$y$};
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[right]{$x$};
end{axis}
end{tikzpicture}
end{document}
Any attempt to draw these unit vectors in the positive x-y plane does IMHO not look good. How about drawing them in the negative x-y plane?
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[below]{$y$};
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[above]{$x$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
Here's a third version with ticks.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[axis on top,xlabel={$x$},ylabel={$y$},
axis lines=middle,xtick={-1,0,1},ytick={-1,0,1},
legend pos=outer north east,
z axis line style={opacity=0},
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
Great! If the graph + vectors is ugly thenf(x,y)in one graph (like your MWE), and vectors in another one (probablyview={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph.:)
– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will bev=(0,-1). Can you find a better view where we could see the 7 vectors with norm1? If "no" then plots it in a new graph withview={0}{90}(if you want).
– manooooh
Oct 27 '18 at 7:17
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:view={-145}{45}->view={145}{45}; added the vectors(-1,0)and(0,-1)(and changed the direction fromdraw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);todraw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and deleteopacity=0.8. Very easy code, thanks!!
– manooooh
Oct 27 '18 at 20:18
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
|
show 2 more comments
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1 Answer
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Here's a proposal. Draw the axes by hand and hide what you have to hide.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={75}{45},clip=false
]
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[right]{$y$};
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[right]{$x$};
end{axis}
end{tikzpicture}
end{document}
Any attempt to draw these unit vectors in the positive x-y plane does IMHO not look good. How about drawing them in the negative x-y plane?
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[below]{$y$};
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[above]{$x$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
Here's a third version with ticks.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[axis on top,xlabel={$x$},ylabel={$y$},
axis lines=middle,xtick={-1,0,1},ytick={-1,0,1},
legend pos=outer north east,
z axis line style={opacity=0},
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
Great! If the graph + vectors is ugly thenf(x,y)in one graph (like your MWE), and vectors in another one (probablyview={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph.:)
– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will bev=(0,-1). Can you find a better view where we could see the 7 vectors with norm1? If "no" then plots it in a new graph withview={0}{90}(if you want).
– manooooh
Oct 27 '18 at 7:17
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:view={-145}{45}->view={145}{45}; added the vectors(-1,0)and(0,-1)(and changed the direction fromdraw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);todraw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and deleteopacity=0.8. Very easy code, thanks!!
– manooooh
Oct 27 '18 at 20:18
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
|
show 2 more comments
2
Here's a proposal. Draw the axes by hand and hide what you have to hide.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={75}{45},clip=false
]
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[right]{$y$};
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[right]{$x$};
end{axis}
end{tikzpicture}
end{document}
Any attempt to draw these unit vectors in the positive x-y plane does IMHO not look good. How about drawing them in the negative x-y plane?
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[below]{$y$};
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[above]{$x$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
Here's a third version with ticks.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[axis on top,xlabel={$x$},ylabel={$y$},
axis lines=middle,xtick={-1,0,1},ytick={-1,0,1},
legend pos=outer north east,
z axis line style={opacity=0},
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
Great! If the graph + vectors is ugly thenf(x,y)in one graph (like your MWE), and vectors in another one (probablyview={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph.:)
– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will bev=(0,-1). Can you find a better view where we could see the 7 vectors with norm1? If "no" then plots it in a new graph withview={0}{90}(if you want).
– manooooh
Oct 27 '18 at 7:17
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:view={-145}{45}->view={145}{45}; added the vectors(-1,0)and(0,-1)(and changed the direction fromdraw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);todraw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and deleteopacity=0.8. Very easy code, thanks!!
– manooooh
Oct 27 '18 at 20:18
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
|
show 2 more comments
2
2
2
Here's a proposal. Draw the axes by hand and hide what you have to hide.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={75}{45},clip=false
]
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[right]{$y$};
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[right]{$x$};
end{axis}
end{tikzpicture}
end{document}
Any attempt to draw these unit vectors in the positive x-y plane does IMHO not look good. How about drawing them in the negative x-y plane?
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[below]{$y$};
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[above]{$x$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
Here's a third version with ticks.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[axis on top,xlabel={$x$},ylabel={$y$},
axis lines=middle,xtick={-1,0,1},ytick={-1,0,1},
legend pos=outer north east,
z axis line style={opacity=0},
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
Here's a proposal. Draw the axes by hand and hide what you have to hide.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={75}{45},clip=false
]
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[right]{$y$};
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[right]{$x$};
end{axis}
end{tikzpicture}
end{document}
Any attempt to draw these unit vectors in the positive x-y plane does IMHO not look good. How about drawing them in the negative x-y plane?
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[hide axis,
legend pos=outer north east,
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[thick,-stealth] (0,0,0) -- (0,4,0) node[below]{$y$};
draw[thick,-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
draw[thick,-stealth] (0,0,0) -- (4,0,0) node[above]{$x$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
Here's a third version with ticks.
documentclass[tikz,border=3.14mm]{standalone}
usepackage{pgfplots}
pgfplotsset{compat=1.16}
begin{document}
begin{tikzpicture}[scale=2,
declare function={f(x,y)=ifthenelse(x*y<0,sqrt(-x*y),-x*x+y);}]
begin{axis}[axis on top,xlabel={$x$},ylabel={$y$},
axis lines=middle,xtick={-1,0,1},ytick={-1,0,1},
legend pos=outer north east,
z axis line style={opacity=0},
view={-145}{45},clip=false
]
addplot3[opacity=0.8,surf,mesh/ordering=y varies,shader=interp,domain=-3:3,domain
y=-3:3,samples=61, samples y=61,on layer=axis background] {f(x,y)};
addlegendentry{$f(x,y)$}
draw[-stealth] (0,0,0) -- (0,0,4) node[right]{$z$};
pgfplotsinvokeforeach{0,22.5,...,90}{%
draw[-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);}
end{axis}
end{tikzpicture}
end{document}
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
edited Oct 27 '18 at 22:50
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
answered Oct 27 '18 at 1:23
marmotmarmot
104k4123234
104k4123234
Great! If the graph + vectors is ugly thenf(x,y)in one graph (like your MWE), and vectors in another one (probablyview={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph.:)
– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will bev=(0,-1). Can you find a better view where we could see the 7 vectors with norm1? If "no" then plots it in a new graph withview={0}{90}(if you want).
– manooooh
Oct 27 '18 at 7:17
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:view={-145}{45}->view={145}{45}; added the vectors(-1,0)and(0,-1)(and changed the direction fromdraw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);todraw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and deleteopacity=0.8. Very easy code, thanks!!
– manooooh
Oct 27 '18 at 20:18
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
|
show 2 more comments
Great! If the graph + vectors is ugly thenf(x,y)in one graph (like your MWE), and vectors in another one (probablyview={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph.:)
– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will bev=(0,-1). Can you find a better view where we could see the 7 vectors with norm1? If "no" then plots it in a new graph withview={0}{90}(if you want).
– manooooh
Oct 27 '18 at 7:17
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:view={-145}{45}->view={145}{45}; added the vectors(-1,0)and(0,-1)(and changed the direction fromdraw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0);todraw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and deleteopacity=0.8. Very easy code, thanks!!
– manooooh
Oct 27 '18 at 20:18
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
Great! If the graph + vectors is ugly then
f(x,y) in one graph (like your MWE), and vectors in another one (probably view={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph. :)– manooooh
Oct 27 '18 at 1:26
Great! If the graph + vectors is ugly then
f(x,y) in one graph (like your MWE), and vectors in another one (probably view={0}{90}). If you find an excellent view where the graph + vectors looks nice, then one graph. :)– manooooh
Oct 27 '18 at 1:26
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will be
v=(0,-1). Can you find a better view where we could see the 7 vectors with norm 1? If "no" then plots it in a new graph with view={0}{90} (if you want).– manooooh
Oct 27 '18 at 7:17
The second part of your question I still don't understand. Do you want to draw these vectors in this plot or in a separate plot? hmmm... now your plot is much better, but I think that the only vector which we could not see will be
v=(0,-1). Can you find a better view where we could see the 7 vectors with norm 1? If "no" then plots it in a new graph with view={0}{90} (if you want).– manooooh
Oct 27 '18 at 7:17
1
1
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
@manooooh Thanks for your edit here. I have a new proposal. What do you think? (I will go cycling now but will be back in a few hours.)
– marmot
Oct 27 '18 at 19:14
You're welcome and awesome!! I only did a few changes:
view={-145}{45} -> view={145}{45}; added the vectors (-1,0) and (0,-1) (and changed the direction from draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0); to draw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and delete opacity=0.8. Very easy code, thanks!!– manooooh
Oct 27 '18 at 20:18
You're welcome and awesome!! I only did a few changes:
view={-145}{45} -> view={145}{45}; added the vectors (-1,0) and (0,-1) (and changed the direction from draw[thick,-stealth] (0,0,0) -- ({-cos(#1)},{-sin(#1)},0); to draw[blue,thick,-stealth] (0,0,0) -- ({cos(#1)},{sin(#1)},0);); and delete opacity=0.8. Very easy code, thanks!!– manooooh
Oct 27 '18 at 20:18
1
1
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
@manooooh If you hide only the z axis and draw it by hand, you can add ticks.
– marmot
Oct 27 '18 at 22:51
|
show 2 more comments
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Probably we should do something with the graph at
x>0andy>0(where the function is-x^2+y) because it is the ugliest part.– manooooh
Oct 26 '18 at 23:28
1
I guess you could improve it somewhat by drawing the plots in a different order: first the plot on the right back, then left back, then right front and finally left front. But it is also a strange function that has jumps. You are sure you want this function?
– marmot
Oct 27 '18 at 0:58
@marmot I want this function. That's a bit better: imgur.com/a/YgRwgwY, anyway I would like to fill the "holes" (and draw the vectors with your help).
– manooooh
Oct 27 '18 at 1:01
Are these two separate graphs or do you want to add the arrows on the first graph? And what do you mean by "fill the holes"? Do you want to plot just one function?
– marmot
Oct 27 '18 at 1:14
@marmot if possible, I want to graph the
7vectors with norm1in3D. That's probably bad (very bad), so the vectors in2D. This is a piecewise function, so all the four graphs are one function (in one graph). The "holes" are that spaces where the function is not plotted.– manooooh
Oct 27 '18 at 1:19