Mrthfx

4 Spheres all touching each other??

For Loop and Sum

It took me a lot of time to make this, pls like. (YouTube Comments #1)

Do commercial flights continue with an engine out?

Can the Count of Monte Cristo's calculation of poison dosage be explained?

Obtaining a matrix of complex values from associations giving the real and imaginary parts of each element?

Do any poskim exempt 13-20-year-olds from Mussaf?

What is the purpose of easy combat scenarios that don't need resource expenditure?

Is my plan for fixing my water heater leak bad?

raspberry pi change directory (cd) command not working with USB drive

Why does the DC-9-80 have this cusp in its fuselage?

Word to be used for "standing with your toes pointing out"

Find the number of ways to express 1050 as sum of consecutive integers

Which branches of mathematics can be done just in terms of morphisms and composition?

What is the meaning of "pick up" in this sentence?

Can I become debt free or should I file for bankruptcy? How do I manage my debt and finances?

How to mitigate "bandwagon attacking" from players?

How would an AI self awareness kill switch work?

'A' vs 'an' in newspaper article

Metadata API deployments are failing in Spring '19

Why do neural networks need so many training examples to perform?

Am I using the wrong word all along?

What is Crew Dragon approaching in this picture?

Is it a fallacy if someone claims they need an explanation for every word of your argument to the point where they don't understand common terms?

Obtaining a matrix of complex values from associations giving the real and imaginary parts of each element?

Eigenvalues of matrix not giving imaginary partsPlot values of an $mtimes n$ matrix on the complex plane with color varying along $m$Real and Imaginary matrixDefining a non-standard algebraic numberFind the parameter values for my matrix for it to have imaginary eigenvaluesEfficiently select the smallest magnitude element from each column of a matrixGenerate random matrix where the entries in each column are drawn from a different rangeSample matrix indices in proportion to the matrix element valuesKeyed eigensystem for nested AssociationConverting a list of associations into a single association

5

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

$endgroup$

add a comment | 

5

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

$endgroup$

add a comment | 

$begingroup$

I have a list of associations keyed by real and imaginary numbers, like so:

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

Given this, I can write

testmatrix = Join[Values[matrix], 2]`

to get a matrix, but it is a matrix of tuples. How can I get the complex number defined in each <|r -> Re[z], i -> Im[z]|> rather than the tuples?

matrix expression-manipulation associations

share|improve this question

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

$endgroup$

matrix = {

   {<|"r" -> 0.368252, "i" -> 0.0199587|>, 

    <|"r" -> -0.461644, "i" -> 0.109868|>, 

    <|"r" -> -0.216081, "i" -> 0.562557|>, 

    <|"r" -> -0.479881, "i" -> -0.212978|>}, 



   {<|"r" -> 0.105028, "i" -> 0.632264|>, 

    <|"r" -> 0.116589, "i" -> -0.490063|>, 

    <|"r" -> 0.463378, "i" -> 0.231656|>,

    <|"r" -> -0.148665, "i" -> 0.212065|>},



   {<|"r" -> 0.463253, "i" -> 0.201161|>,

    <|"r" -> 0.460547, "i" -> 0.397829|>,

    <|"r" -> 0.222257, "i" -> 0.0129121|>,

    <|"r" -> 0.168641, "i" -> -0.544568|>},



   {<|"r" -> 0.255221, "i" -> -0.364687|>,

    <|"r" -> 0.191895, "i" -> -0.337437|>,

    <|"r" -> -0.12278, "i" -> 0.551195|>,

    <|"r" -> 0.560485, "i" -> 0.134702|>}

}

testmatrix = Join[Values[matrix], 2]`

share|improve this question

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

share|improve this question

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

edited 1 hour ago

MarcoB

36.6k556112

edited 1 hour ago

MarcoB

36.6k556112

asked 8 hours ago

MKFMKF

1588

asked 8 hours ago

MKFMKF

1588

2 Answers
2

active

oldest

votes

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 4 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  28 mins ago
  

  
  
  
  

add a comment | 

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 1 hour ago

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  30 mins ago
  

  
  
  
  

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192530%2fobtaining-a-matrix-of-complex-values-from-associations-giving-the-real-and-imagi%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 4 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  28 mins ago
  

  
  
  
  

add a comment | 

6

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 4 hours ago

kglrkglr

186k10203422

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Huh, that's a great one! A word of warning though: This method produces unpacked arrays.
  $endgroup$
  – Henrik Schumacher
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  The Apply[Complex] method will also fail if the entries are not integers or inexact real numbers, e.g. Complex @@ {Pi, Sqrt[2]}.
  $endgroup$
  – J. M. is computer-less♦
  28 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

Apply[Complex, matrix, {2}]

{{0.368252 +0.0199587 I,-0.461644+0.109868 I,-0.216081+0.562557 I,-0.479881-0.212978 I},

{0.105028 +0.632264 I,0.116589 -0.490063 I,0.463378 +0.231656 I,-0.148665+0.212065 I},

{0.463253 +0.201161 I,0.460547 +0.397829 I,0.222257 +0.0129121 I,0.168641 -0.544568 I},

{0.255221 -0.364687 I,0.191895 -0.337437 I,-0.12278+0.551195 I,0.560485 +0.134702 I}}

share|improve this answer

answered 4 hours ago

kglrkglr

186k10203422

$endgroup$

Apply[Complex, matrix, {2}]

share|improve this answer

answered 4 hours ago

kglrkglr

186k10203422

answered 4 hours ago

kglrkglr

186k10203422

answered 4 hours ago

kglrkglr

186k10203422

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 1 hour ago

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  30 mins ago
  

  
  
  
  

add a comment | 

5

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 1 hour ago

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Even better: Values[matrix].{1, I}, which preserves the matrix structure.
  $endgroup$
  – J. M. is computer-less♦
  30 mins ago
  

  
  
  
  

add a comment | 

$begingroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

or

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 1 hour ago

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

$endgroup$

matrix[[All, All, "r"]] + I matrix[[All, All, "i"]]

Join[Values[matrix], 2].{1, I}

share|improve this answer

edited 1 hour ago

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154

answered 8 hours ago

Henrik SchumacherHenrik Schumacher

55.3k576154