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$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
webmathematica mathematica-online
edited 1 hour ago
David G. Stork
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
webmathematica mathematica-online
edited 1 hour ago
David G. Stork
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
$endgroup$
add a comment |
$begingroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
webmathematica mathematica-online
edited 1 hour ago
David G. Stork
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
$endgroup$
How does one color the interior of the elongated circular region in the following figure:
ContourPlot[y^2 - x (x - 1)(x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
webmathematica mathematica-online
webmathematica mathematica-online
edited 1 hour ago
David G. Stork
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
edited 1 hour ago
David G. Stork
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
edited 1 hour ago
David G. Stork
24.8k22155
edited 1 hour ago
David G. Stork
24.8k22155
edited 1 hour ago
David G. Stork
24.8k22155
24.8k22155
asked 2 hours ago
Sara yaqobSara yaqob
134
asked 2 hours ago
Sara yaqobSara yaqob
134
asked 2 hours ago
Sara yaqobSara yaqob
134
134
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
answered 2 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 hours ago
XminerXminer
19918
$endgroup$
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
add a comment |
$begingroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 hours ago
XminerXminer
19918
$endgroup$
Try without "==0"
ContourPlot[y^2 - x (x - 1) (x - 3), {x, -2, 7}, {y, -4, 3}]
answered 2 hours ago
XminerXminer
19918
answered 2 hours ago
XminerXminer
19918
answered 2 hours ago
XminerXminer
19918
answered 2 hours ago
XminerXminer
19918
19918
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
add a comment |
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
But I need only the curve not the surface
$endgroup$
– Sara yaqob
2 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
answered 2 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
answered 2 hours ago
mjwmjw
9679
$endgroup$
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
add a comment |
$begingroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
answered 2 hours ago
mjwmjw
9679
$endgroup$
I am assuming you mean that you would like to color the round object in the plot (not really a circle):
Your plot
c = ContourPlot[y^2 - x (x - 1) (x - 3) == 0, {x, -2, 7}, {y, -4, 3}]
The region you would like colored
R = RegionPlot[y^2 - x (x - 1) (x - 3) < 0 && x < 2, {x, -2, 7}, {y, -4, 3}]
Both plotted together
Show[c, R]
answered 2 hours ago
mjwmjw
9679
edited 2 hours ago
answered 2 hours ago
mjwmjw
9679
answered 2 hours ago
mjwmjw
9679
answered 2 hours ago
mjwmjw
9679
9679
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
add a comment |
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
1
1
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
Thank you so so much sir. That's what I need.
$endgroup$
– Sara yaqob
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sara, You are welcome!
$endgroup$
– mjw
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
$begingroup$
@Sarayaqob you mistakenly accepted my answer
$endgroup$
– Xminer
2 hours ago
add a comment |
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