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Relationship between strut and baselineskip


strut and strutboxHow to modify columns/column environments so they resize automatically to the largest column ?Set strut heightDefinition of strut explainedStrutting around: What's the difference between strut, mathstrut and vphantom?Ensuring a paragraph uses at least a given height?Why is `strut` working in these scenarios?Variable-width horizontal rules with cline intrude cell textFirst word hyphenation in parbox with strutbaselineskip param of fontsize doesn't add space between my lines













1















Here, it is said that a strut is defined as:



rule[-.3baselineskip]{0pt}{baselineskip}


However, if I do:



newlength{strutheight}
settoheight{strutheight}{strut}printlength{strutheight}
printlength{baselineskip}


It prints:



8.39996pt 12.0pt


8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?










share|improve this question



























    1















    Here, it is said that a strut is defined as:



    rule[-.3baselineskip]{0pt}{baselineskip}


    However, if I do:



    newlength{strutheight}
    settoheight{strutheight}{strut}printlength{strutheight}
    printlength{baselineskip}


    It prints:



    8.39996pt 12.0pt


    8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?










    share|improve this question

























      1












      1








      1








      Here, it is said that a strut is defined as:



      rule[-.3baselineskip]{0pt}{baselineskip}


      However, if I do:



      newlength{strutheight}
      settoheight{strutheight}{strut}printlength{strutheight}
      printlength{baselineskip}


      It prints:



      8.39996pt 12.0pt


      8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?










      share|improve this question














      Here, it is said that a strut is defined as:



      rule[-.3baselineskip]{0pt}{baselineskip}


      However, if I do:



      newlength{strutheight}
      settoheight{strutheight}{strut}printlength{strutheight}
      printlength{baselineskip}


      It prints:



      8.39996pt 12.0pt


      8.39996 is equal to 0.7*12. However, what I don't understand is that according to its definition the height of the strut should be baselineskip, because -.3baselineskip only refers to a vertical alignment offset. Why does settoheight on a strut produces this behaviour?







      vertical-alignment baseline calc strut






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 13 mins ago









      VincentVincent

      1,69221939




      1,69221939






















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