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pgfplots - draw boxplot without outliers
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I am creating a boxplot with pgfplots, using the builtin statistics library. I load the input data from a table file.
usepackage{pgfplots}
usepgfplotslibrary{statistics}
...
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y]
addplot+[boxplot] table[
col sep=tab,
x expr=coordindex,
y=aColName] {aFileName};
end{axis}
end{tikzpicture}
Is it possible to draw the plot without outliers? Or hide them? I don't want to pre-calculate the boxplot values by hand.
pgfplots statistics boxplot
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
add a comment |
I am creating a boxplot with pgfplots, using the builtin statistics library. I load the input data from a table file.
usepackage{pgfplots}
usepgfplotslibrary{statistics}
...
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y]
addplot+[boxplot] table[
col sep=tab,
x expr=coordindex,
y=aColName] {aFileName};
end{axis}
end{tikzpicture}
Is it possible to draw the plot without outliers? Or hide them? I don't want to pre-calculate the boxplot values by hand.
pgfplots statistics boxplot
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
add a comment |
I am creating a boxplot with pgfplots, using the builtin statistics library. I load the input data from a table file.
usepackage{pgfplots}
usepgfplotslibrary{statistics}
...
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y]
addplot+[boxplot] table[
col sep=tab,
x expr=coordindex,
y=aColName] {aFileName};
end{axis}
end{tikzpicture}
Is it possible to draw the plot without outliers? Or hide them? I don't want to pre-calculate the boxplot values by hand.
pgfplots statistics boxplot
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
I am creating a boxplot with pgfplots, using the builtin statistics library. I load the input data from a table file.
usepackage{pgfplots}
usepgfplotslibrary{statistics}
...
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y]
addplot+[boxplot] table[
col sep=tab,
x expr=coordindex,
y=aColName] {aFileName};
end{axis}
end{tikzpicture}
Is it possible to draw the plot without outliers? Or hide them? I don't want to pre-calculate the boxplot values by hand.
pgfplots statistics boxplot
pgfplots statistics boxplot
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
edited Jun 3 '13 at 10:23
Claudio Fiandrino
52.9k11156314
52.9k11156314
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
asked Jun 3 '13 at 10:14
EntropiaEntropia
334
334
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
If you add the following code snippet to your preamble, you can use hide outliers to locally disable plotting the outliers:
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
documentclass{article}
usepackage{pgfplots}
usepgfplotslibrary{statistics}
begin{document}
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot, hide outliers]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
end{document}
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
I tried your sample both on my local Latex as well as on Overleaf and I always getPackage pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.
– schneida
Mar 31 at 13:01
add a comment |
Just for completeness here is a solution using the combination of 'R-knitr-LaTeX'.
documentclass[border=5mm]{standalone}
begin{document}
<<echo=FALSE>>=
#par(pin=c(5,.1))
#par(mar=c(.2,.2,.2,.2))
par(bty="n")
#par(mai=c(.35,.35,.35,.35),omi=c(0,0,0,0))
par(mfrow=c(2,1))
x=c(1,2,1,5,4,10,7,10,9,8,9,9,21)
boxplot(x,horizontal=TRUE,outline=TRUE,plot=TRUE,axes=TRUE)
axis(side=1, at=c(0,5,10,15,20))
boxplot(x,horizontal=TRUE,outline=FALSE,plot=TRUE, col='lightblue',axes=TRUE)
axis(side=1, at=c(0,2,4,6,8,10))
@
end{document}
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
add a comment |
I have simply done that by just adding mark=. to addplot+[boxplot]
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y,]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
% box plot without outliers
addplot+[boxplot, mark=.]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
answered 5 mins ago
sisamansisaman
81
add a comment |
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3 Answers
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3 Answers
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oldest
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If you add the following code snippet to your preamble, you can use hide outliers to locally disable plotting the outliers:
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
documentclass{article}
usepackage{pgfplots}
usepgfplotslibrary{statistics}
begin{document}
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot, hide outliers]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
end{document}
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
I tried your sample both on my local Latex as well as on Overleaf and I always getPackage pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.
– schneida
Mar 31 at 13:01
add a comment |
If you add the following code snippet to your preamble, you can use hide outliers to locally disable plotting the outliers:
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
documentclass{article}
usepackage{pgfplots}
usepgfplotslibrary{statistics}
begin{document}
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot, hide outliers]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
end{document}
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
I tried your sample both on my local Latex as well as on Overleaf and I always getPackage pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.
– schneida
Mar 31 at 13:01
add a comment |
If you add the following code snippet to your preamble, you can use hide outliers to locally disable plotting the outliers:
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
documentclass{article}
usepackage{pgfplots}
usepgfplotslibrary{statistics}
begin{document}
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot, hide outliers]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
end{document}
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
If you add the following code snippet to your preamble, you can use hide outliers to locally disable plotting the outliers:
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
documentclass{article}
usepackage{pgfplots}
usepgfplotslibrary{statistics}
begin{document}
makeatletter
pgfplotsset{
boxplot/hide outliers/.code={
defpgfplotsplothandlerboxplot@outlier{}%
}
}
makeatother
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
begin{tikzpicture}
begin{axis}[y=1cm, try min ticks=2]
addplot+[boxplot, hide outliers]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
end{document}
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
edited Jun 10 '17 at 13:06
David Carlisle
499k4111451895
499k4111451895
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
answered Jun 3 '13 at 11:45
JakeJake
196k24660765
196k24660765
I tried your sample both on my local Latex as well as on Overleaf and I always getPackage pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.
– schneida
Mar 31 at 13:01
add a comment |
I tried your sample both on my local Latex as well as on Overleaf and I always getPackage pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.
– schneida
Mar 31 at 13:01
I tried your sample both on my local Latex as well as on Overleaf and I always get
Package pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.– schneida
Mar 31 at 13:01
I tried your sample both on my local Latex as well as on Overleaf and I always get
Package pgfkeys Error: I do not know the key '/tikz/hide outliers' and I amd going to ignore it.– schneida
Mar 31 at 13:01
add a comment |
Just for completeness here is a solution using the combination of 'R-knitr-LaTeX'.
documentclass[border=5mm]{standalone}
begin{document}
<<echo=FALSE>>=
#par(pin=c(5,.1))
#par(mar=c(.2,.2,.2,.2))
par(bty="n")
#par(mai=c(.35,.35,.35,.35),omi=c(0,0,0,0))
par(mfrow=c(2,1))
x=c(1,2,1,5,4,10,7,10,9,8,9,9,21)
boxplot(x,horizontal=TRUE,outline=TRUE,plot=TRUE,axes=TRUE)
axis(side=1, at=c(0,5,10,15,20))
boxplot(x,horizontal=TRUE,outline=FALSE,plot=TRUE, col='lightblue',axes=TRUE)
axis(side=1, at=c(0,2,4,6,8,10))
@
end{document}
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
add a comment |
Just for completeness here is a solution using the combination of 'R-knitr-LaTeX'.
documentclass[border=5mm]{standalone}
begin{document}
<<echo=FALSE>>=
#par(pin=c(5,.1))
#par(mar=c(.2,.2,.2,.2))
par(bty="n")
#par(mai=c(.35,.35,.35,.35),omi=c(0,0,0,0))
par(mfrow=c(2,1))
x=c(1,2,1,5,4,10,7,10,9,8,9,9,21)
boxplot(x,horizontal=TRUE,outline=TRUE,plot=TRUE,axes=TRUE)
axis(side=1, at=c(0,5,10,15,20))
boxplot(x,horizontal=TRUE,outline=FALSE,plot=TRUE, col='lightblue',axes=TRUE)
axis(side=1, at=c(0,2,4,6,8,10))
@
end{document}
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
add a comment |
Just for completeness here is a solution using the combination of 'R-knitr-LaTeX'.
documentclass[border=5mm]{standalone}
begin{document}
<<echo=FALSE>>=
#par(pin=c(5,.1))
#par(mar=c(.2,.2,.2,.2))
par(bty="n")
#par(mai=c(.35,.35,.35,.35),omi=c(0,0,0,0))
par(mfrow=c(2,1))
x=c(1,2,1,5,4,10,7,10,9,8,9,9,21)
boxplot(x,horizontal=TRUE,outline=TRUE,plot=TRUE,axes=TRUE)
axis(side=1, at=c(0,5,10,15,20))
boxplot(x,horizontal=TRUE,outline=FALSE,plot=TRUE, col='lightblue',axes=TRUE)
axis(side=1, at=c(0,2,4,6,8,10))
@
end{document}
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
Just for completeness here is a solution using the combination of 'R-knitr-LaTeX'.
documentclass[border=5mm]{standalone}
begin{document}
<<echo=FALSE>>=
#par(pin=c(5,.1))
#par(mar=c(.2,.2,.2,.2))
par(bty="n")
#par(mai=c(.35,.35,.35,.35),omi=c(0,0,0,0))
par(mfrow=c(2,1))
x=c(1,2,1,5,4,10,7,10,9,8,9,9,21)
boxplot(x,horizontal=TRUE,outline=TRUE,plot=TRUE,axes=TRUE)
axis(side=1, at=c(0,5,10,15,20))
boxplot(x,horizontal=TRUE,outline=FALSE,plot=TRUE, col='lightblue',axes=TRUE)
axis(side=1, at=c(0,2,4,6,8,10))
@
end{document}
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
answered May 30 '15 at 2:11
R. SchumacherR. Schumacher
8,50122239
8,50122239
add a comment |
add a comment |
I have simply done that by just adding mark=. to addplot+[boxplot]
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y,]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
% box plot without outliers
addplot+[boxplot, mark=.]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
answered 5 mins ago
sisamansisaman
81
add a comment |
I have simply done that by just adding mark=. to addplot+[boxplot]
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y,]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
% box plot without outliers
addplot+[boxplot, mark=.]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
answered 5 mins ago
sisamansisaman
81
add a comment |
I have simply done that by just adding mark=. to addplot+[boxplot]
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y,]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
% box plot without outliers
addplot+[boxplot, mark=.]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
answered 5 mins ago
sisamansisaman
81
I have simply done that by just adding mark=. to addplot+[boxplot]
begin{tikzpicture}
begin{axis}[boxplot/draw direction=y,]
addplot+[boxplot]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
% box plot without outliers
addplot+[boxplot, mark=.]
table[row sep=\,y index=0] {
data\
1\ 2\ 1\ 5\ 4\ 10\
7\ 10\ 9\ 8\ 9\ 9\
21\
};
end{axis}
end{tikzpicture}
answered 5 mins ago
sisamansisaman
81
answered 5 mins ago
sisamansisaman
81
answered 5 mins ago
sisamansisaman
81
answered 5 mins ago
sisamansisaman
81
81
add a comment |
add a comment |
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