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Plot a graph above a curve with vertical lines as pattern


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0















I want to plot the graph of a function (say a sine) on a curve, that is to say, plot the graph above a straight line then distort it into a given curve.



Here's a minimal example :



documentclass[pstricks,border=12pt]{standalone}  
usepackage[left=4.0cm,right=4.0cm,top=4.0cm,bottom=4.0cm]{geometry}
usepackage{tikz}
usetikzlibrary{patterns}
usepackage{pgfplots}
usepackage{caption}
usepackage{amsmath,amssymb,amsthm}
usepackage{xcolor}
usetikzlibrary{arrows}
%
%
begin{document}
%
%
%
begin{figure}[!h]
centering
captionsetup{justification=centering,margin=2cm}
begin{tikzpicture}[scale=1.0]
%
draw[](-4,0)--(4,0);
%
draw [red, thick] plot [pattern = vertical lines, rotate = 0, domain = -4:4, samples = 120] (x,{0.5*sin(x*180)});
%
begin{scope} [shift={(0.0,0.0)}]
draw [blue, thick] plot [rotate = 0.0, domain = -4.0:4.0, samples = 80] (x,{-1.65*(x*x-16)/16});
end{scope}
%
end{tikzpicture}
caption{label{Name}Bla bla...}
end{figure}
%
%
%
end{document}


I first plot a horizontal straight line then plot a sine function above it (observe here that the pattern function does not work ; what am I doing wrong here ?). Then, I would like to plot say the same sine function but "above" the blue curve, as if the graph was following the blue curve.










share|improve this question



























    0















    I want to plot the graph of a function (say a sine) on a curve, that is to say, plot the graph above a straight line then distort it into a given curve.



    Here's a minimal example :



    documentclass[pstricks,border=12pt]{standalone}  
    usepackage[left=4.0cm,right=4.0cm,top=4.0cm,bottom=4.0cm]{geometry}
    usepackage{tikz}
    usetikzlibrary{patterns}
    usepackage{pgfplots}
    usepackage{caption}
    usepackage{amsmath,amssymb,amsthm}
    usepackage{xcolor}
    usetikzlibrary{arrows}
    %
    %
    begin{document}
    %
    %
    %
    begin{figure}[!h]
    centering
    captionsetup{justification=centering,margin=2cm}
    begin{tikzpicture}[scale=1.0]
    %
    draw[](-4,0)--(4,0);
    %
    draw [red, thick] plot [pattern = vertical lines, rotate = 0, domain = -4:4, samples = 120] (x,{0.5*sin(x*180)});
    %
    begin{scope} [shift={(0.0,0.0)}]
    draw [blue, thick] plot [rotate = 0.0, domain = -4.0:4.0, samples = 80] (x,{-1.65*(x*x-16)/16});
    end{scope}
    %
    end{tikzpicture}
    caption{label{Name}Bla bla...}
    end{figure}
    %
    %
    %
    end{document}


    I first plot a horizontal straight line then plot a sine function above it (observe here that the pattern function does not work ; what am I doing wrong here ?). Then, I would like to plot say the same sine function but "above" the blue curve, as if the graph was following the blue curve.










    share|improve this question

























      0












      0








      0








      I want to plot the graph of a function (say a sine) on a curve, that is to say, plot the graph above a straight line then distort it into a given curve.



      Here's a minimal example :



      documentclass[pstricks,border=12pt]{standalone}  
      usepackage[left=4.0cm,right=4.0cm,top=4.0cm,bottom=4.0cm]{geometry}
      usepackage{tikz}
      usetikzlibrary{patterns}
      usepackage{pgfplots}
      usepackage{caption}
      usepackage{amsmath,amssymb,amsthm}
      usepackage{xcolor}
      usetikzlibrary{arrows}
      %
      %
      begin{document}
      %
      %
      %
      begin{figure}[!h]
      centering
      captionsetup{justification=centering,margin=2cm}
      begin{tikzpicture}[scale=1.0]
      %
      draw[](-4,0)--(4,0);
      %
      draw [red, thick] plot [pattern = vertical lines, rotate = 0, domain = -4:4, samples = 120] (x,{0.5*sin(x*180)});
      %
      begin{scope} [shift={(0.0,0.0)}]
      draw [blue, thick] plot [rotate = 0.0, domain = -4.0:4.0, samples = 80] (x,{-1.65*(x*x-16)/16});
      end{scope}
      %
      end{tikzpicture}
      caption{label{Name}Bla bla...}
      end{figure}
      %
      %
      %
      end{document}


      I first plot a horizontal straight line then plot a sine function above it (observe here that the pattern function does not work ; what am I doing wrong here ?). Then, I would like to plot say the same sine function but "above" the blue curve, as if the graph was following the blue curve.










      share|improve this question














      I want to plot the graph of a function (say a sine) on a curve, that is to say, plot the graph above a straight line then distort it into a given curve.



      Here's a minimal example :



      documentclass[pstricks,border=12pt]{standalone}  
      usepackage[left=4.0cm,right=4.0cm,top=4.0cm,bottom=4.0cm]{geometry}
      usepackage{tikz}
      usetikzlibrary{patterns}
      usepackage{pgfplots}
      usepackage{caption}
      usepackage{amsmath,amssymb,amsthm}
      usepackage{xcolor}
      usetikzlibrary{arrows}
      %
      %
      begin{document}
      %
      %
      %
      begin{figure}[!h]
      centering
      captionsetup{justification=centering,margin=2cm}
      begin{tikzpicture}[scale=1.0]
      %
      draw[](-4,0)--(4,0);
      %
      draw [red, thick] plot [pattern = vertical lines, rotate = 0, domain = -4:4, samples = 120] (x,{0.5*sin(x*180)});
      %
      begin{scope} [shift={(0.0,0.0)}]
      draw [blue, thick] plot [rotate = 0.0, domain = -4.0:4.0, samples = 80] (x,{-1.65*(x*x-16)/16});
      end{scope}
      %
      end{tikzpicture}
      caption{label{Name}Bla bla...}
      end{figure}
      %
      %
      %
      end{document}


      I first plot a horizontal straight line then plot a sine function above it (observe here that the pattern function does not work ; what am I doing wrong here ?). Then, I would like to plot say the same sine function but "above" the blue curve, as if the graph was following the blue curve.







      tikz-pgf tikz-styles pattern






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 28 mins ago









      NicolasNicolas

      827




      827






















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