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Else If is not working on algorithm in algpseudocode
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)How to change Algorithm title to something else?Algorithm indent problem with sig-alternate document & algorithm(ic) packageInserting multiple columns in algorithmStart algorithm step numbering not at 1if-else inside for loop in algorithm packageInput and output in latex algorithmThere is always a zero at the end of my algorithmwriting a data structure in an algorithmAlgorithm returning 0The algorithm does not execute in IEEE transaction template. Please help
I tried to add Else
in my pseudocode but it is not showing and I am getting 'Missing number, treated as zero'. This is my code and the current outcome.
usepackage{algorithm}
usepackage[noend]{algpseudocode}
begin{algorithm}
caption{Homomorphism: Query Containment}label{alg:euclid}
begin{algorithmic}[1]
Function{getHomorphism}{XPath $p_3$, XPath $q_3$}
ForAll {nodes.getLength}
State ($q_3(root)$ == $p_3(root)$) $leftarrow$ textbf{true}
State textbf{return} true
If{true}
ForAll {descendantNodes.getLength}
State textbf{return} true
If {true}
ForAll {childNodes.getLength}
State textbf{return} true
If {true}
ForAll {wildcardNodes.getLength}
State textbf{return} true
Else
State textbf{return} false
EndIf
EndFunction
end{algorithmic}
end{algorithm}
algorithms algorithmic algpseudocode
New contributor
add a comment |
I tried to add Else
in my pseudocode but it is not showing and I am getting 'Missing number, treated as zero'. This is my code and the current outcome.
usepackage{algorithm}
usepackage[noend]{algpseudocode}
begin{algorithm}
caption{Homomorphism: Query Containment}label{alg:euclid}
begin{algorithmic}[1]
Function{getHomorphism}{XPath $p_3$, XPath $q_3$}
ForAll {nodes.getLength}
State ($q_3(root)$ == $p_3(root)$) $leftarrow$ textbf{true}
State textbf{return} true
If{true}
ForAll {descendantNodes.getLength}
State textbf{return} true
If {true}
ForAll {childNodes.getLength}
State textbf{return} true
If {true}
ForAll {wildcardNodes.getLength}
State textbf{return} true
Else
State textbf{return} false
EndIf
EndFunction
end{algorithmic}
end{algorithm}
algorithms algorithmic algpseudocode
New contributor
add a comment |
I tried to add Else
in my pseudocode but it is not showing and I am getting 'Missing number, treated as zero'. This is my code and the current outcome.
usepackage{algorithm}
usepackage[noend]{algpseudocode}
begin{algorithm}
caption{Homomorphism: Query Containment}label{alg:euclid}
begin{algorithmic}[1]
Function{getHomorphism}{XPath $p_3$, XPath $q_3$}
ForAll {nodes.getLength}
State ($q_3(root)$ == $p_3(root)$) $leftarrow$ textbf{true}
State textbf{return} true
If{true}
ForAll {descendantNodes.getLength}
State textbf{return} true
If {true}
ForAll {childNodes.getLength}
State textbf{return} true
If {true}
ForAll {wildcardNodes.getLength}
State textbf{return} true
Else
State textbf{return} false
EndIf
EndFunction
end{algorithmic}
end{algorithm}
algorithms algorithmic algpseudocode
New contributor
I tried to add Else
in my pseudocode but it is not showing and I am getting 'Missing number, treated as zero'. This is my code and the current outcome.
usepackage{algorithm}
usepackage[noend]{algpseudocode}
begin{algorithm}
caption{Homomorphism: Query Containment}label{alg:euclid}
begin{algorithmic}[1]
Function{getHomorphism}{XPath $p_3$, XPath $q_3$}
ForAll {nodes.getLength}
State ($q_3(root)$ == $p_3(root)$) $leftarrow$ textbf{true}
State textbf{return} true
If{true}
ForAll {descendantNodes.getLength}
State textbf{return} true
If {true}
ForAll {childNodes.getLength}
State textbf{return} true
If {true}
ForAll {wildcardNodes.getLength}
State textbf{return} true
Else
State textbf{return} false
EndIf
EndFunction
end{algorithmic}
end{algorithm}
algorithms algorithmic algpseudocode
algorithms algorithmic algpseudocode
New contributor
New contributor
edited 4 mins ago
user6185827
New contributor
asked 10 mins ago
user6185827user6185827
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11
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user6185827 is a new contributor. Be nice, and check out our Code of Conduct.
user6185827 is a new contributor. Be nice, and check out our Code of Conduct.
user6185827 is a new contributor. Be nice, and check out our Code of Conduct.
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