Mrthfx

If infinitesimal transformations commute why dont the generators of the Lorentz group commute?

Why electric field inside a cavity of a non-conducting sphere not zero?

How to bake one texture for one mesh with multiple textures blender 2.8

Lowest total scrabble score

Open a doc from terminal, but not by its name

What was the exact wording from Ivanhoe of this advice on how to free yourself from slavery?

Are the IPv6 address space and IPv4 address space completely disjoint?

What if a revenant (monster) gains fire resistance?

On a tidally locked planet, would time be quantized?

When were female captains banned from Starfleet?

Longest common substring in linear time

copy and scale one figure (wheel)

What is Cash Advance APR?

GraphicsGrid with a Label for each Column and Row

Freedom of speech and where it applies

What is the evidence for the "tyranny of the majority problem" in a direct democracy context?

Creepy dinosaur pc game identification

why `nmap 192.168.1.97` returns less services than `nmap 127.0.0.1`?

Should I outline or discovery write my stories?

Not using 's' for he/she/it

Are paving bricks differently sized for sand bedding vs mortar bedding?

Existing of non-intersecting rays

Melting point of aspirin, contradicting sources

How should I respond when I lied about my education and the company finds out through background check?

Create all possible words using a set or letters

Finding all length-n words on an alphabet that have a specified number of each letterFinding all dictionary words that can be made with a given set of characters (Wordfeud/Scrabble)How to enumerate all possible binary associations?Sorting an Array with words in different languagesUsing StringCases and treating certain phrases as single wordsGraph showing valid English words obtained by insertion of single charactersTrim a list of elementsList all possible microstates and corresponding energy using mathematica.Selecting words having a specific number of letters from a textSelecting elements using two lists

1

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

add a comment | 

1

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

add a comment | 

$begingroup$

Given a list of letters,

letters = { "A", "B", ..., "F" }

is it possible to get Mathematica to generate all ‘words’ (in this example, 6 letter words), if only one letter can be used one time only, e.g. ABCDEF, ABCDFE, …? TIA.

string-manipulation combinatorics

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

$endgroup$

letters = { "A", "B", ..., "F" }

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

share|improve this question

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

edited 1 hour ago

J. M. is slightly pensive♦

98.3k10306466

asked 1 hour ago

mf67mf67

975

asked 1 hour ago

mf67mf67

975

2 Answers
2

active

oldest

votes

3

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

46027

$endgroup$

add a comment | 

2

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193857%2fcreate-all-possible-words-using-a-set-or-letters%23new-answer', 'question_page');
}
);

Post as a guest

Name

Email

Required, but never shown

3

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

46027

$endgroup$

add a comment | 

3

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

46027

$endgroup$

add a comment | 

$begingroup$

You can create permutations with all of the letters as strings with:

StringJoin /@ Permutations[letters]

If you want lists of the individual letters just use:

Permutations[letters]

Check the documentation of Permutations to learn about permutations with subsets of letters. If you want to use each letter more than once, look at the documentation for Tuples.

share|improve this answer

answered 1 hour ago

LeeLee

46027

$endgroup$

StringJoin /@ Permutations[letters]

Permutations[letters]

share|improve this answer

answered 1 hour ago

LeeLee

46027

answered 1 hour ago

LeeLee

46027

answered 1 hour ago

LeeLee

46027

2

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

2

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

add a comment | 

$begingroup$

Pemutations will do it:

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

$endgroup$

letters = {"a", "b", "c"};

Permutations[letters, {3}]

{{"a", "b", "c"}, {"a", "c", "b"}, {"b", "a", "c"}, 

 {"b", "c", "a"}, {"c", "a", "b"}, {"c", "b", "a"}}

share|improve this answer

answered 1 hour ago

bill sbill s

54.6k377156

answered 1 hour ago

bill sbill s

54.6k377156

answered 1 hour ago

bill sbill s

54.6k377156