Im stuck and having trouble with ￢P ∨ Q Prove: P → Q Planned maintenance scheduled April...
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Im stuck and having trouble with ￢P ∨ Q Prove: P → Q
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I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
111
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Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am having trouble with this problem as I have just started doing logic. Is this the same as P → Q Prove: ￢P ∨ Q?
logic
logic
asked 4 hours ago
Hamish DochertyHamish Docherty
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 4 hours ago
Hamish DochertyHamish Docherty
111
asked 4 hours ago
Hamish DochertyHamish Docherty
111
111
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Hamish Docherty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
2
2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago
add a comment |
1 Answer
1
active
oldest
votes
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 1 hour ago
Graham KempGraham Kemp
1,04418
add a comment |
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1 Answer
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1 Answer
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oldest
votes
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active
oldest
votes
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 1 hour ago
Graham KempGraham Kemp
1,04418
add a comment |
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 1 hour ago
Graham KempGraham Kemp
1,04418
add a comment |
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 1 hour ago
Graham KempGraham Kemp
1,04418
In a natural deduction system (if that is what you are using) to prove a conditional, such as is P → Q, you must use a Conditional
Proof.
This takes the form of assuming the antecedent (that is P) aiming to derive the consequent (that is Q) through valid inferences (also using the premises; that is ￢P ∨ Q). Then discharging the assumption allow the deduction of the conditional (that is P → Q).
Now to prove Q from an assumption of P and the premise of ￢P ∨ Q, either use Disjunctive Syllogism, or a Proof by Cases.
answered 1 hour ago
Graham KempGraham Kemp
1,04418
answered 1 hour ago
Graham KempGraham Kemp
1,04418
answered 1 hour ago
Graham KempGraham Kemp
1,04418
answered 1 hour ago
Graham KempGraham Kemp
1,04418
1,04418
add a comment |
add a comment |
Hamish Docherty is a new contributor. Be nice, and check out our Code of Conduct.
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2
Which text book are you using? An online proof checker and text book may be helpful as supplementary material: proofs.openlogicproject.org
– Frank Hubeny
4 hours ago