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Drawing a parametric line with unitary director vector produces a longer straight line using `PGFPlots`


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0















I would like to plot a normal bounded line to a surface in a point.



The surface is y=x and the point is (1/2,1/2,1). The gradient is (-1,1,0), and at point (1/2,1/2,1) is still the same, thus the normal line would be (x-1/2)/(-1)=(y-1/2)/(1)=(z-1)/(0), hence the line is described by (.5,.5,1)+t(-1,1,0).



However, I want the line to be bounded, in order to make a unitary director vector, but I am not able to do these. I am using t between 0 and 1, but these draw a long line; I want it to be a vector of length 1.



I am not sure if this math is correct. If I find the unitary vector of (-1,1,0) it is (-1,1,0)/(sqrt(2)) i.e. (-sqrt(2)/2,sqrt(2)/2,0) then I still do not have a vector of length 1 (when t is between 0 and 1).



Here is my MWE:



documentclass{article}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

usepackage{pgfplots}
pgfplotsset{compat=1.15}

begin{document}

begin{center}
begin{tikzpicture}
begin{axis} [
title={Without normalizing $(-1,1,0)$ ($tin[0,1]$)},
axis on top,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
ticklabel style={font=tiny},
view={115}{25}
]
addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
addplot3[-stealth,variable=t,domain=0:1] ({1/2+t},{1/2-t},{1});
end{axis}
end{tikzpicture}
hfill
begin{tikzpicture}
begin{axis} [
title={Normalizing $(-1,1,0)$ ($tin[0,1]$)},
axis on top,
axis lines=center,
xlabel=$x$,
ylabel=$y$,
zlabel=$z$,
ticklabel style={font=tiny},
view={115}{25}
]
addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
addplot3[-stealth,variable=t,domain=0:1] ({1/2+(sqrt(2)/2)*t},{1/2-(sqrt(2)/2)*t},{1});
end{axis}
end{tikzpicture}
end{center}

end{document}


MWE



Even the line has a bad quality, it looks pixelated:



Pixelated line



Does anyone know how to produce a vector of length 1 or what am I missing?



Some links of interest:





  • pgfplots: positioning a normal and tangent vector on a 3d surface

  • Find a good view for a function by parts using tikzpicture environment [Overleaf]


Thanks!!









share





























    0















    I would like to plot a normal bounded line to a surface in a point.



    The surface is y=x and the point is (1/2,1/2,1). The gradient is (-1,1,0), and at point (1/2,1/2,1) is still the same, thus the normal line would be (x-1/2)/(-1)=(y-1/2)/(1)=(z-1)/(0), hence the line is described by (.5,.5,1)+t(-1,1,0).



    However, I want the line to be bounded, in order to make a unitary director vector, but I am not able to do these. I am using t between 0 and 1, but these draw a long line; I want it to be a vector of length 1.



    I am not sure if this math is correct. If I find the unitary vector of (-1,1,0) it is (-1,1,0)/(sqrt(2)) i.e. (-sqrt(2)/2,sqrt(2)/2,0) then I still do not have a vector of length 1 (when t is between 0 and 1).



    Here is my MWE:



    documentclass{article}
    usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

    usepackage{pgfplots}
    pgfplotsset{compat=1.15}

    begin{document}

    begin{center}
    begin{tikzpicture}
    begin{axis} [
    title={Without normalizing $(-1,1,0)$ ($tin[0,1]$)},
    axis on top,
    axis lines=center,
    xlabel=$x$,
    ylabel=$y$,
    zlabel=$z$,
    ticklabel style={font=tiny},
    view={115}{25}
    ]
    addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
    addplot3[-stealth,variable=t,domain=0:1] ({1/2+t},{1/2-t},{1});
    end{axis}
    end{tikzpicture}
    hfill
    begin{tikzpicture}
    begin{axis} [
    title={Normalizing $(-1,1,0)$ ($tin[0,1]$)},
    axis on top,
    axis lines=center,
    xlabel=$x$,
    ylabel=$y$,
    zlabel=$z$,
    ticklabel style={font=tiny},
    view={115}{25}
    ]
    addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
    addplot3[-stealth,variable=t,domain=0:1] ({1/2+(sqrt(2)/2)*t},{1/2-(sqrt(2)/2)*t},{1});
    end{axis}
    end{tikzpicture}
    end{center}

    end{document}


    MWE



    Even the line has a bad quality, it looks pixelated:



    Pixelated line



    Does anyone know how to produce a vector of length 1 or what am I missing?



    Some links of interest:





    • pgfplots: positioning a normal and tangent vector on a 3d surface

    • Find a good view for a function by parts using tikzpicture environment [Overleaf]


    Thanks!!









    share



























      0












      0








      0








      I would like to plot a normal bounded line to a surface in a point.



      The surface is y=x and the point is (1/2,1/2,1). The gradient is (-1,1,0), and at point (1/2,1/2,1) is still the same, thus the normal line would be (x-1/2)/(-1)=(y-1/2)/(1)=(z-1)/(0), hence the line is described by (.5,.5,1)+t(-1,1,0).



      However, I want the line to be bounded, in order to make a unitary director vector, but I am not able to do these. I am using t between 0 and 1, but these draw a long line; I want it to be a vector of length 1.



      I am not sure if this math is correct. If I find the unitary vector of (-1,1,0) it is (-1,1,0)/(sqrt(2)) i.e. (-sqrt(2)/2,sqrt(2)/2,0) then I still do not have a vector of length 1 (when t is between 0 and 1).



      Here is my MWE:



      documentclass{article}
      usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

      usepackage{pgfplots}
      pgfplotsset{compat=1.15}

      begin{document}

      begin{center}
      begin{tikzpicture}
      begin{axis} [
      title={Without normalizing $(-1,1,0)$ ($tin[0,1]$)},
      axis on top,
      axis lines=center,
      xlabel=$x$,
      ylabel=$y$,
      zlabel=$z$,
      ticklabel style={font=tiny},
      view={115}{25}
      ]
      addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
      addplot3[-stealth,variable=t,domain=0:1] ({1/2+t},{1/2-t},{1});
      end{axis}
      end{tikzpicture}
      hfill
      begin{tikzpicture}
      begin{axis} [
      title={Normalizing $(-1,1,0)$ ($tin[0,1]$)},
      axis on top,
      axis lines=center,
      xlabel=$x$,
      ylabel=$y$,
      zlabel=$z$,
      ticklabel style={font=tiny},
      view={115}{25}
      ]
      addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
      addplot3[-stealth,variable=t,domain=0:1] ({1/2+(sqrt(2)/2)*t},{1/2-(sqrt(2)/2)*t},{1});
      end{axis}
      end{tikzpicture}
      end{center}

      end{document}


      MWE



      Even the line has a bad quality, it looks pixelated:



      Pixelated line



      Does anyone know how to produce a vector of length 1 or what am I missing?



      Some links of interest:





      • pgfplots: positioning a normal and tangent vector on a 3d surface

      • Find a good view for a function by parts using tikzpicture environment [Overleaf]


      Thanks!!









      share
















      I would like to plot a normal bounded line to a surface in a point.



      The surface is y=x and the point is (1/2,1/2,1). The gradient is (-1,1,0), and at point (1/2,1/2,1) is still the same, thus the normal line would be (x-1/2)/(-1)=(y-1/2)/(1)=(z-1)/(0), hence the line is described by (.5,.5,1)+t(-1,1,0).



      However, I want the line to be bounded, in order to make a unitary director vector, but I am not able to do these. I am using t between 0 and 1, but these draw a long line; I want it to be a vector of length 1.



      I am not sure if this math is correct. If I find the unitary vector of (-1,1,0) it is (-1,1,0)/(sqrt(2)) i.e. (-sqrt(2)/2,sqrt(2)/2,0) then I still do not have a vector of length 1 (when t is between 0 and 1).



      Here is my MWE:



      documentclass{article}
      usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}

      usepackage{pgfplots}
      pgfplotsset{compat=1.15}

      begin{document}

      begin{center}
      begin{tikzpicture}
      begin{axis} [
      title={Without normalizing $(-1,1,0)$ ($tin[0,1]$)},
      axis on top,
      axis lines=center,
      xlabel=$x$,
      ylabel=$y$,
      zlabel=$z$,
      ticklabel style={font=tiny},
      view={115}{25}
      ]
      addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
      addplot3[-stealth,variable=t,domain=0:1] ({1/2+t},{1/2-t},{1});
      end{axis}
      end{tikzpicture}
      hfill
      begin{tikzpicture}
      begin{axis} [
      title={Normalizing $(-1,1,0)$ ($tin[0,1]$)},
      axis on top,
      axis lines=center,
      xlabel=$x$,
      ylabel=$y$,
      zlabel=$z$,
      ticklabel style={font=tiny},
      view={115}{25}
      ]
      addplot3[opacity=.5,surf,samples=21,variable=t,variable y=s,domain=0:2,y domain=0:90,z buffer=sort,colormap={red}{color=(red) color=(red)}] ({t*cos(s)*(sqrt(2)*.5)},{t*cos(s)*(sqrt(2)*.5)},{t*sin(s)});%Red S
      addplot3[-stealth,variable=t,domain=0:1] ({1/2+(sqrt(2)/2)*t},{1/2-(sqrt(2)/2)*t},{1});
      end{axis}
      end{tikzpicture}
      end{center}

      end{document}


      MWE



      Even the line has a bad quality, it looks pixelated:



      Pixelated line



      Does anyone know how to produce a vector of length 1 or what am I missing?



      Some links of interest:





      • pgfplots: positioning a normal and tangent vector on a 3d surface

      • Find a good view for a function by parts using tikzpicture environment [Overleaf]


      Thanks!!







      tikz-pgf





      share














      share












      share



      share








      edited 1 min ago







      manooooh

















      asked 8 mins ago









      manoooohmanooooh

      1,1221516




      1,1221516






















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